Math Problem Statement

Give the domain and range of the quadratic function whose graph is described. Minimum = -4 at x = 2.

Solution

The problem is asking for the domain and range of a quadratic function, with the given information that the minimum value of the function is 4-4 at x=2x = 2.

Domain:

The domain of a quadratic function, which is of the form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, is always all real numbers because quadratic functions are defined for every value of xx. Therefore, the domain in interval notation is: (,)\boxed{(-\infty, \infty)}

Range:

Since the quadratic function has a minimum value of 4-4 at x=2x = 2, this means the parabola opens upwards (i.e., the coefficient of x2x^2 is positive). Therefore, the range is all values of yy greater than or equal to 4-4. The range in interval notation is: [4,)\boxed{[-4, \infty)}

Would you like more details on how the domain and range are derived or have any other questions?

Here are five related questions you might find helpful:

  1. What is the general form of a quadratic function, and how can you determine its direction (upward or downward)?
  2. How does the vertex of a quadratic function relate to its minimum or maximum value?
  3. What is the difference between the domain and range of a function?
  4. How can you find the vertex of a quadratic function from its equation?
  5. Can the range of a quadratic function ever be all real numbers?

Tip: Always check the direction (upwards or downwards) of the parabola when determining the range of a quadratic function.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Domain and Range

Formulas

f(x) = ax^2 + bx + c

Theorems

Properties of Quadratic Functions

Suitable Grade Level

Grades 8-10