Math Problem Statement
Find the domain and the range of the piecewise function: f(x) = (3/7)x + 5 for x < 7 and f(x) = 2 for x ≥ 7.
Solution
To determine the domain of the given function , we analyze each part:
The function is defined as:
\begin{cases} \frac{3}{7}x + 5 & \text{for } x < 7 \\ 2 & \text{for } x \geq 7 \end{cases}$$ ### Step 1: Analyzing the Domain 1. For $$x < 7$$, the expression $$\frac{3}{7}x + 5$$ is valid for all values of $$x$$ less than 7. There are no restrictions here. 2. For $$x \geq 7$$, $$f(x) = 2$$ is valid for all values of $$x \geq 7$$. ### Combining the two parts The function $$f(x)$$ is therefore defined for all $$x$$ such that $$x \in (-\infty, \infty)$$. ### Domain in interval notation The domain of the function in interval notation is: $$(-\infty, \infty)$$ Would you like more details, or do you have any further questions? ### Here are 5 related questions: 1. What is the range of the given function $$f(x)$$? 2. How do we determine the continuity of this piecewise function at $$x = 7$$? 3. What is the behavior of the function as $$x \to -\infty$$? 4. How would the graph of this piecewise function look? 5. What changes in the domain if $$f(x) = \frac{3}{7}x + 5$$ were restricted to $$x \leq 0$$ instead? ### Tip: When working with piecewise functions, always consider each interval separately and then combine them to find the overall domain and range.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Piecewise Functions
Algebra
Functions
Formulas
f(x) = (3/7)x + 5
f(x) = 2
Theorems
Domain and Range Theorems
Suitable Grade Level
Grade 10-12
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