Math Problem Statement

Given f(x)=7x2+42x+71f(x)=7x2+42x+71,     −3≤x≤5-3≤x≤5.

Identify the Domain and Range of f−1(x)f-1(x)

Solution

To identify the domain and range of the inverse function f1(x)f^{-1}(x), we first need to understand the domain and range of the original function f(x)f(x).

Given the function f(x)=7x2+42x+71f(x) = 7x^2 + 42x + 71 with the domain 3x5-3 \leq x \leq 5:

  1. Domain of f(x)f(x): The domain is the set of all input values xx for the function. Here, it is given directly as 3x5-3 \leq x \leq 5.

  2. Range of f(x)f(x): The range is the set of all possible output values y=f(x)y = f(x) within the given domain. To find the range, we need to evaluate f(x)f(x) at the endpoints and at the vertex of the parabola, as the function is quadratic (a parabola).

    • Finding the vertex: The vertex xx-coordinate for a parabola ax2+bx+cax^2 + bx + c is given by x=b2ax = -\frac{b}{2a}. Here, a=7a = 7 and b=42b = 42. x=422(7)=3x = -\frac{42}{2(7)} = -3 Since the vertex occurs at x=3x = -3, this value lies within the domain.

    • Calculating the function value at x=3x = -3 (vertex): f(3)=7(3)2+42(3)+71=7(9)126+71=63126+71=8f(-3) = 7(-3)^2 + 42(-3) + 71 = 7(9) - 126 + 71 = 63 - 126 + 71 = 8

    • Calculating the function value at x=5x = 5: f(5)=7(5)2+42(5)+71=7(25)+210+71=175+210+71=456f(5) = 7(5)^2 + 42(5) + 71 = 7(25) + 210 + 71 = 175 + 210 + 71 = 456

    So, the range of f(x)f(x) is [8,456][8, 456].

  3. Domain and Range of f1(x)f^{-1}(x):

    • The domain of f1(x)f^{-1}(x) is the range of f(x)f(x), so Domain of f1(x)=[8,456]\text{Domain of } f^{-1}(x) = [8, 456].
    • The range of f1(x)f^{-1}(x) is the domain of f(x)f(x), so Range of f1(x)=[3,5]\text{Range of } f^{-1}(x) = [-3, 5].

Summary:

  • Domain of f1(x)f^{-1}(x): [8,456][8, 456]
  • Range of f1(x)f^{-1}(x): [3,5][-3, 5]

Would you like a detailed explanation or have any other questions?

Here are five questions related to this problem:

  1. How do you derive the formula for the vertex of a quadratic function?
  2. What is the significance of finding the vertex in the context of this problem?
  3. How would the domain and range change if the interval for xx was different?
  4. What would happen to the domain and range of f1(x)f^{-1}(x) if the parabola opened downwards?
  5. Can the inverse of any quadratic function always be found?

Tip: Always double-check the vertex calculations when dealing with quadratic functions, as they determine the range for the function and hence the domain of its inverse.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Inverse Functions
Domain and Range

Formulas

Vertex formula for a quadratic function

Theorems

-

Suitable Grade Level

Grades 10-12