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To solve this problem, let's analyze each part:

### Part (a): Domain of \( f(x) \)

Given:
\[
f(x) = \frac{x}{x^2 + 7x + 10}
\]

To find the domain of \( f(x) \), we need to determine when the denominator \( x^2 + 7x + 10 \) is zero, as division by zero is undefined.

1. Factor the denominator:
   \[
   x^2 + 7x + 10 = (x + 5)(x + 2)
   \]

2. Set each factor to zero:
   \[
   x + 5 = 0 \Rightarrow x = -5
   \]
   \[
   x + 2 = 0 \Rightarrow x = -2
   \]

3. Therefore, \( f(x) \) is undefined at \( x = -5 \) and \( x = -2 \).

Thus, the domain of \( f(x) \) in interval notation is:
\[
(-\infty, -5) \cup (-5, -2) \cup (-2, \infty)
\]

### Part (b): Intervals of Increase and Decrease

To determine where \( f(x) \) is increasing or decreasing, we need to analyze the derivative \( f'(x) \).

1. **Compute \( f'(x) \)** using the quotient rule:
   \[
   f(x) = \frac{x}{x^2 + 7x + 10}
   \]
   Let \( u = x \) and \( v = x^2 + 7x + 10 \). Then \( u' = 1 \) and \( v' = 2x + 7 \).
   \[
   f'(x) = \frac{v \cdot u' - u \cdot v'}{v^2} = \frac{(x^2 + 7x + 10) \cdot 1 - x \cdot (2x + 7)}{(x^2 + 7x + 10)^2}
   \]

2. Simplify \( f'(x) \):
   Expanding the numerator:
   \[
   f'(x) = \frac{x^2 + 7x + 10 - (2x^2 + 7x)}{(x^2 + 7x + 10)^2} = \frac{-x^2 + 10}{(x^2 + 7x + 10)^2}
   \]

3. Set \( f'(x) = 0 \) to find critical points:
   \[
   -x^2 + 10 = 0 \Rightarrow x^2 = 10 \Rightarrow x = \pm \sqrt{10}
   \]

4. Test intervals around \( x = -\sqrt{10} \) and \( x = \sqrt{10} \) to determine the sign of \( f'(x) \).

After analysis, we find that:

- \( f(x) \) is **increasing** on \( (-\infty, -\sqrt{10}) \cup (\sqrt{10}, \infty) \)
- \( f(x) \) is **decreasing** on \( (-\sqrt{10}, \sqrt{10}) \)

### Final Answers:

- **Domain:** \((- \infty, -5) \cup (-5, -2) \cup (-2, \infty)\)
- **Increasing on:** \((- \infty, -\sqrt{10}) \cup (\sqrt{10}, \infty)\)
- **Decreasing on:** \((- \sqrt{10}, \sqrt{10})\)

Would you like more details on any step, or do you have any questions?

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Here are five related questions that expand on this information:

1. How would the domain change if the function were \( f(x) = \frac{x}{x^2 + 7x - 10} \)?
2. What happens to the intervals of increase and decrease if we add a constant to \( f(x) \)?
3. How does the behavior of the function near its vertical asymptotes affect its graph?
4. What are some strategies for determining critical points without explicitly finding the derivative?
5. Can you determine the concavity of \( f(x) \) by using the second derivative?

**Tip:** When analyzing rational functions, always check for undefined points in the denominator to find the domain first.

Given \( f(x) = \frac{x}{x^2 + 7x + 10} \), find the domain of \( f \) in interval notation. Then, determine the intervals on which \( f \) is increasing and decreasing.

Learn how to determine the domain and intervals of increase and decrease for the rational function f(x) = x/(x^2 + 7x + 10). This problem involves factoring, identifying undefined points, and applying the quotient rule for derivatives. Suitable for advanced high school students in Grades 11-12.

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