Math Problem Statement
Solution
Let's break down the solution and explain it step by step.
(a) Domain of
The function is undefined where the denominator equals zero: Factoring: Thus, and are the points where the function is undefined. Therefore, the domain of in interval notation is:
(b) Critical Numbers
Critical numbers occur where the derivative of , , is zero or undefined. Calculating using the quotient rule: Simplify the numerator: So, Set the numerator equal to zero to find critical points: Thus, the critical numbers are:
(c) Increasing and Decreasing Intervals
Analyze the sign of around the critical points and where is undefined ().
-
Test intervals:
-
Sign of :
- on (increasing).
- on (decreasing).
So, is:
- Increasing on .
- Decreasing on .
(d) Relative Extrema (First Derivative Test)
-
At :
- changes from negative to positive.
- Thus, is a relative minimum.
-
At :
- changes from positive to negative.
- Thus, is a relative maximum.
Summary:
- Relative maxima:
- Relative minima:
Recap:
- Domain:
- Critical numbers:
- Increasing:
- Decreasing:
- Relative maxima:
- Relative minima:
Do you want a detailed explanation of any specific part? Here are some questions for further exploration:
- How is the derivative computed using the quotient rule?
- Why do critical points only occur where or undefined?
- How do we test intervals to determine increasing or decreasing behavior?
- What happens to near undefined points ()?
- Can we verify these results graphically?
Tip: Always factorize carefully and check for undefined points in rational functions.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Critical Points
Quotient Rule
Increasing and Decreasing Functions
Relative Extrema
Formulas
Quotient Rule: (u/v)' = (u'v - uv') / v^2
Derivative of f(x) = x / (x^2 + 10x + 21)
f'(x) = (-x^2 + 21) / (x^2 + 10x + 21)^2
Theorems
First Derivative Test
Zero Derivative Rule for Critical Points
Suitable Grade Level
Grades 11-12 or College Calculus I