To determine which number is divisible by 8, we need to check if the last three digits of each number are divisible by 8. Let's go through each option:

• a. 9208: The last three digits are 208.
  $208 \div 8 = 26$ (no remainder)
  So, 9208 is divisible by 8.

• b. 6236: The last three digits are 236.
  $236 \div 8 = 29.5$ (remainder)
  So, 6236 is not divisible by 8.

• c. 88254: The last three digits are 254.
  $254 \div 8 = 31.75$ (remainder)
  So, 88254 is not divisible by 8.

• d. 8886: The last three digits are 886.
  $886 \div 8 = 110.75$ (remainder)
  So, 8886 is not divisible by 8.

Therefore, the only number divisible by 8 is 9208.

Would you like more details or have any further questions? Here are some related questions to explore:

1. Why does a number need to have its last three digits divisible by 8 to be divisible by 8?
2. What is the divisibility rule for 4, and how is it related to the divisibility rule for 8?
3. How can we determine if a large number is divisible by other divisors like 9 or 11?
4. Can the divisibility rules for numbers like 3 and 6 also be applied to large numbers in a similar way?
5. What are the other divisibility rules for numbers between 1 and 12?

Tip: Remember that for divisibility by 8, it's sufficient to check the last three digits of the number.