Math Problem Statement

Divide $430 into 3 parts such that A gets 5/4 of B and the ratio between B and C is 3 : 4.

Solution

Let the three parts be AA, BB, and CC.

Step 1: Set Up Relationships Between Parts

  1. Given that AA gets 54\frac{5}{4} of BB, we can write: A=54BA = \frac{5}{4}B

  2. The ratio between BB and CC is given as 3:43:4. So, we can express CC in terms of BB: BC=34    C=43B\frac{B}{C} = \frac{3}{4} \implies C = \frac{4}{3}B

Step 2: Express Total Sum

The total sum of the parts is given as 430430: A+B+C=430A + B + C = 430

Substituting the expressions for AA and CC in terms of BB: 54B+B+43B=430\frac{5}{4}B + B + \frac{4}{3}B = 430

Step 3: Simplify the Equation

Combine the terms by finding a common denominator. The common denominator of 4 and 3 is 12.

  1. Convert each term: 54B=1512B,B=1212B,43B=1612B\frac{5}{4}B = \frac{15}{12}B, \quad B = \frac{12}{12}B, \quad \frac{4}{3}B = \frac{16}{12}B

  2. Adding them: 1512B+1212B+1612B=4312B\frac{15}{12}B + \frac{12}{12}B + \frac{16}{12}B = \frac{43}{12}B

Thus, the equation becomes: 4312B=430\frac{43}{12}B = 430

Step 4: Solve for BB

Multiply both sides by

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Math Problem Analysis

Mathematical Concepts

Algebra
Ratios and Proportions
Linear Equations

Formulas

A = (5/4)B
B/C = 3/4
A + B + C = 430

Theorems

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Suitable Grade Level

Grades 9-12