Math Problem Statement

Divide 2060 between three people x, y and z such that x gets the three fifth of what y gets and the ratio of the share of y to z is 6:11

Solution

Let's solve the problem step by step.

Step 1: Define the shares of xx, yy, and zz.

  • Let the share of yy be yy.
  • The share of xx is 35\frac{3}{5} of yy, so x=35yx = \frac{3}{5} y.
  • The ratio of the share of yy to zz is 6:11, so yz=611\frac{y}{z} = \frac{6}{11}, or equivalently, z=116yz = \frac{11}{6} y.

Step 2: Write the total sum equation.

The total sum of the shares of xx, yy, and zz is 2060, so:

x+y+z=2060x + y + z = 2060

Substitute the expressions for xx and zz:

35y+y+116y=2060\frac{3}{5} y + y + \frac{11}{6} y = 2060

Step 3: Solve for yy.

To simplify the equation, get rid of the fractions by multiplying through by the least common denominator (LCD), which is 30:

30(35y)+30(y)+30(116y)=30(2060)30 \left( \frac{3}{5} y \right) + 30(y) + 30 \left( \frac{11}{6} y \right) = 30(2060)

This simplifies to:

18y+30y+55y=6180018y + 30y + 55y = 61800

Combine the terms:

103y=61800103y = 61800

Now, solve for yy:

y=61800103=600y = \frac{61800}{103} = 600

Step 4: Find xx and zz.

Now that we have y=600y = 600, we can find xx and zz:

  • x=35×600=360x = \frac{3}{5} \times 600 = 360
  • z=116×600=1100z = \frac{11}{6} \times 600 = 1100

Step 5: Verify the solution.

Check if the sum of xx, yy, and zz equals 2060:

x+y+z=360+600+1100=2060x + y + z = 360 + 600 + 1100 = 2060

The solution is correct.

Final Answer:

  • x=360x = 360
  • y=600y = 600
  • z=1100z = 1100

Would you like further details or have any questions?


Here are 5 related questions for practice:

  1. Divide 1800 between three people such that the first gets 47\frac{4}{7} of the second, and the ratio of the second to third is 5:9.
  2. If x=49yx = \frac{4}{9} y and yz=7:12\frac{y}{z} = 7:12, divide 2400 between them.
  3. Find the shares if 3200 is divided such that x=58yx = \frac{5}{8} y and the ratio of yy to zz is 2:7.
  4. Divide 1540 between xx, yy, and zz, where x=23yx = \frac{2}{3} y and y:z=3:5y:z = 3:5.
  5. In a sum of 5000, the ratio of xx to yy is 2:5 and the ratio of yy to zz is 3:4.

Tip: Always check your final result by verifying that the sum of all parts matches the given total!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Ratio and Proportion
Linear Equations

Formulas

x = (3/5) * y
z = (11/6) * y
x + y + z = 2060

Theorems

Basic Proportionality Theorem

Suitable Grade Level

Grades 8-10