Math Problem Statement

The DECI-Pizza Company has a special pizza that has 10 slices. Two of the slices are each 1/6 of the whole pizza, two are each 1/8 , four are each 1/12 , and two are each 1/24 . A group of n friends share the pizza by distributing all of these slices. They do not cut any of the slices. Each of the n friends receives, in total, an equal fraction of the whole pizza. For what values of n > 1 is this possible

Solution

We are given that the DECI-Pizza Company has a pizza divided into 10 slices with the following proportions:

  • Two slices are each 16\frac{1}{6} of the pizza.
  • Two slices are each 18\frac{1}{8}.
  • Four slices are each 112\frac{1}{12}.
  • Two slices are each 124\frac{1}{24}.

The total pizza must be shared equally among nn friends, and we need to determine for which values of n>1n > 1 this is possible.

Step 1: Calculate the total fraction of the pizza

Let's first calculate the total amount of pizza, which should sum up to 1.

  • Two slices of 16\frac{1}{6} contribute: 2×16=26=132 \times \frac{1}{6} = \frac{2}{6} = \frac{1}{3}
  • Two slices of 18\frac{1}{8} contribute: 2×18=28=142 \times \frac{1}{8} = \frac{2}{8} = \frac{1}{4}
  • Four slices of 112\frac{1}{12} contribute: 4×112=412=134 \times \frac{1}{12} = \frac{4}{12} = \frac{1}{3}
  • Two slices of 124\frac{1}{24} contribute: 2×124=224=1122 \times \frac{1}{24} = \frac{2}{24} = \frac{1}{12}

Now, let's sum all the contributions: 13+14+13+112\frac{1}{3} + \frac{1}{4} + \frac{1}{3} + \frac{1}{12}

To add these fractions, we need a common denominator. The least common denominator of 3, 4, and 12 is 12.

  • 13=412\frac{1}{3} = \frac{4}{12}
  • 14=312\frac{1}{4} = \frac{3}{12}
  • 13=412\frac{1}{3} = \frac{4}{12}
  • 112=112\frac{1}{12} = \frac{1}{12}

Summing these: 412+312+412+112=1212=1\frac{4}{12} + \frac{3}{12} + \frac{4}{12} + \frac{1}{12} = \frac{12}{12} = 1 Thus, the total pizza is indeed the whole pizza.

Step 2: Determine the values of nn

Now, the task is to distribute the pizza equally among nn friends. Each friend should receive an equal fraction of the total pizza.

The slices are 16\frac{1}{6}, 18\frac{1}{8}, 112\frac{1}{12}, and 124\frac{1}{24}, and we cannot cut the slices. The total pizza must be divided equally, so the total fraction each person receives must be a divisor of 1.

Let's check the smallest slice size, which is 124\frac{1}{24}. This indicates that nn must divide the total number of "units" in the pizza, where each "unit" corresponds to 124\frac{1}{24} of the pizza.

Thus, nn must divide the least common multiple (LCM) of the denominators: 6, 8, 12, and 24.

Step 3: Find the least common multiple (LCM)

The LCM of 6, 8, 12, and 24 is calculated by finding the prime factorizations:

  • 6=2×36 = 2 \times 3
  • 8=238 = 2^3
  • 12=22×312 = 2^2 \times 3
  • 24=23×324 = 2^3 \times 3

The LCM is obtained by taking the highest powers of all prime factors: LCM(6,8,12,24)=23×3=24\text{LCM}(6, 8, 12, 24) = 2^3 \times 3 = 24

Thus, the total pizza can be divided into 24 equal parts.

Step 4: Determine the divisors of 24

The values of nn that allow the pizza to be shared equally are the divisors of 24. These divisors are: 1,2,3,4,6,8,12,241, 2, 3, 4, 6, 8, 12, 24

Since n>1n > 1, the possible values of nn are: n=2,3,4,6,8,12,24n = 2, 3, 4, 6, 8, 12, 24

Conclusion:

The possible values of n>1n > 1 for which the pizza can be shared equally among nn friends are: n=2,3,4,6,8,12,24n = 2, 3, 4, 6, 8, 12, 24

Would you like more details or have any questions? Here are five related questions:

  1. How do you calculate the least common multiple (LCM) for other sets of numbers?
  2. Why can't slices be further divided in this problem?
  3. How would the solution change if different slice sizes were introduced?
  4. What if the total number of slices was different, but with the same proportions?
  5. How would the solution be affected if n=5n = 5 friends shared the pizza?

Tip: Always check the LCM when dividing portions equally across multiple people without cutting pieces further.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Fractions
Least Common Multiple (LCM)
Division
Number Theory

Formulas

LCM(a, b, c, ...) = Product of highest powers of all prime factors
Sum of fractions with different denominators by finding the least common denominator

Theorems

Divisibility Theorem
LCM Theorem

Suitable Grade Level

Grades 7-10