Math Problem Statement

Find the distance from the point (3, 5, 5) to the line given by the parametric equations: x = 0, y = 5 + 4t, z = 5 + 5t.

Solution

The problem you're working on asks to find the distance from the point (3,5,5)(3, 5, 5) to the line given by the parametric equations:

x=0,y=5+4t,z=5+5tx = 0, \quad y = 5 + 4t, \quad z = 5 + 5t

To solve this, we can use the formula for the distance from a point to a line in 3D:

d=A×BBd = \frac{| \mathbf{A} \times \mathbf{B} |}{| \mathbf{B} |}

Where:

  • A\mathbf{A} is the vector from a point on the line (we can use (0,5,5)(0, 5, 5), the point when t=0t = 0) to the point (3,5,5)(3, 5, 5).
  • B\mathbf{B} is the direction vector of the line, which is 0,4,5\langle 0, 4, 5 \rangle based on the parametric equations.

Let's compute the necessary vectors and steps to find the distance.

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Math Problem Analysis

Mathematical Concepts

Vector Geometry
Distance in 3D Space
Cross Product
Parametric Equations

Formulas

Distance from a point to a line: d = |(A × B)| / |B|
Cross product formula
Magnitude of a vector formula

Theorems

Distance Formula in 3D
Vector Cross Product Theorem

Suitable Grade Level

College-Level (Calculus and Linear Algebra)