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Let's go through the problem:

The question involves two segments of a journey:
1. **First segment:** The person rides a motorbike from their house to a bus station, covering this distance at a speed of \( 36 \, \text{km/h} \) towards the West in \( 10 \) minutes.
2. **Second segment:** They then take a bus that travels south at \( 48 \, \text{km/h} \) for \( 30 \) minutes.

The problem asks:
- **(a)** To find the total distance traveled and the speed for the entire journey.
- **(b)** To determine the total displacement (in terms of both direction and magnitude) and the average velocity of the person for the entire trip.

Let's solve each part.

### Part (a): Total Distance and Speed
1. **First segment distance**:
   - Speed: \( 36 \, \text{km/h} \)
   - Time: \( 10 \) minutes \( = \frac{10}{60} = \frac{1}{6} \) hours
   - Distance: \( 36 \times \frac{1}{6} = 6 \, \text{km} \)

2. **

A person rides a motorbike from home to a bus station, covering this distance at a speed of 36 km/h towards the West in 10 minutes. After reaching the bus station, they take a bus traveling south at 48 km/h for 30 minutes.

(a) Calculate the total distance and speed for the entire journey.
(b) Determine the total displacement (including direction and magnitude) and the average velocity for the whole trip.

Solve a physics problem involving a two-part journey: calculating the total distance, average speed, displacement, and velocity. The person travels at 36 km/h on a motorbike and 48 km/h on a bus, with times of 10 and 30 minutes. Suitable for high school students in Grades 10-12.

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