To find the distance the bus travels between Hawkes Meadow and Brunswick Street, we need to use the relationship:

$\text{Distance} = \text{Speed} \times \text{Time}$

Step-by-Step Solution:

1. Identify the Speed: The bus travels at an average speed of 29 km/h between Hawkes Meadow and Brunswick Street.

2. Calculate the Time:

   • At Hawkes Meadow, the time is 14:25.
   • At Brunswick Street, the time is 14:40.
   • The time difference is 14:40 - 14:25, which equals 15 minutes.

3. Convert Time to Hours:

   • Since the speed is in km/h, we need the time in hours.
   • 15 minutes is equal to $\frac{15}{60} = 0.25$ hours.

4. Calculate the Distance: $\text{Distance} = 29 \, \text{km/h} \times 0.25 \, \text{hours} = 7.25 \, \text{km}$

Answer:

The bus travels 7.3 km (rounded to 1 decimal place) between Hawkes Meadow and Brunswick Street.

Would you like further details or have any questions?

Here are some related questions to deepen your understanding:

1. How would the distance change if the average speed were increased to 35 km/h?
2. What would be the new travel time between the stops if the distance remained the same but the speed dropped to 20 km/h?
3. How would we calculate the total distance traveled if all stops' distances were given in a similar way?
4. If the bus encountered a delay at Brunswick Street, how would that affect the calculation?
5. How would you convert the answer to meters instead of kilometers?

Tip: Always ensure units are consistent when using formulas for speed, distance, and time calculations.