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To find the distance the bus travels between Hawkes Meadow and Brunswick Street, we need to use the relationship:

\[
\text{Distance} = \text{Speed} \times \text{Time}
\]

### Step-by-Step Solution:
1. **Identify the Speed**: The bus travels at an average speed of 29 km/h between Hawkes Meadow and Brunswick Street.

2. **Calculate the Time**:
   - At Hawkes Meadow, the time is 14:25.
   - At Brunswick Street, the time is 14:40.
   - The time difference is 14:40 - 14:25, which equals 15 minutes.
   
3. **Convert Time to Hours**:
   - Since the speed is in km/h, we need the time in hours.
   - 15 minutes is equal to \( \frac{15}{60} = 0.25 \) hours.

4. **Calculate the Distance**:
   \[
   \text{Distance} = 29 \, \text{km/h} \times 0.25 \, \text{hours} = 7.25 \, \text{km}
   \]

### Answer:
The bus travels **7.3 km** (rounded to 1 decimal place) between Hawkes Meadow and Brunswick Street.

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Would you like further details or have any questions?

Here are some related questions to deepen your understanding:
1. How would the distance change if the average speed were increased to 35 km/h?
2. What would be the new travel time between the stops if the distance remained the same but the speed dropped to 20 km/h?
3. How would we calculate the total distance traveled if all stops' distances were given in a similar way?
4. If the bus encountered a delay at Brunswick Street, how would that affect the calculation?
5. How would you convert the answer to meters instead of kilometers?

**Tip:** Always ensure units are consistent when using formulas for speed, distance, and time calculations.

The average speed of the bus between Hawkes Meadow and Brunswick Street is 29 km/h. Work out how many kilometres the bus travels between these two stops. If your answer is a decimal, give it to 1 decimal place.

Learn how to calculate the distance traveled by a bus between two stops using its average speed (29 km/h) and travel time. Step-by-step solution included, with the answer rounded to 1 decimal place. Suitable for Grades 7-9.

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