To find the length of the interval $AB$, we can use the distance formula between two points. The distance formula is:

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

From the graph:

• Point $A$ is located at $(-3, 5)$.
• Point $B$ is located at $(6, -3)$.

Substitute these coordinates into the formula:

$AB = \sqrt{(6 - (-3))^2 + (-3 - 5)^2}$

Simplify each part of the equation:

1. $x_2 - x_1 = 6 - (-3) = 6 + 3 = 9$
2. $y_2 - y_1 = -3 - 5 = -8$

Now square these results:

$AB = \sqrt{(9)^2 + (-8)^2} = \sqrt{81 + 64} = \sqrt{145}$

So, the length of $AB$ is:

$AB = \sqrt{145} \approx 12.04$

Therefore, $AB \approx 12.04$ units.

Would you like more details or have any further questions?

Here are some related questions you might find interesting:

1. How would you calculate the midpoint of the interval $AB$?
2. What would change in the calculation if point $B$ were at $(6, 3)$?
3. How do you interpret the distance formula geometrically?
4. Can the distance formula be applied in three-dimensional space, and if so, how?
5. What is the significance of the sign of coordinates in distance calculations?

Tip: Remember, when using the distance formula, always square the differences in coordinates to avoid any negative impact on the calculation, as distance is always non-negative.