Math Problem Statement

work out this math question

Find the length of the interval AB.

Solution

To find the length of the interval ABAB between points AA and BB on the coordinate plane, we can use the distance formula:

AB=(x2x1)2+(y2y1)2AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

From the image:

  • Point AA has coordinates (2,2)(2, 2).
  • Point BB has coordinates (6,5)(6, 5).

Substitute these values into the formula: AB=(62)2+(52)2AB = \sqrt{(6 - 2)^2 + (5 - 2)^2}

Calculate step-by-step:

  1. 62=46 - 2 = 4 and 52=35 - 2 = 3.
  2. Square these results: 42=164^2 = 16 and 32=93^2 = 9.
  3. Add the squares: 16+9=2516 + 9 = 25.
  4. Take the square root: 25=5\sqrt{25} = 5.

So, the length of the interval ABAB is: AB=5AB = 5

Would you like further details on this solution or have any other questions?


Here are five related questions to deepen understanding:

  1. What is the distance formula, and why does it work for finding the length between two points?
  2. How would the length of ABAB change if point BB were at (6,6)(6, 6)?
  3. What is the midpoint of the line segment ABAB with points AA at (2,2)(2, 2) and BB at (6,5)(6, 5)?
  4. How can the distance formula be derived from the Pythagorean theorem?
  5. How would you calculate the distance between two points in three-dimensional space?

Tip: Always double-check the coordinates before substituting them into the distance formula to avoid simple errors.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Between Points

Formulas

Distance formula: AB = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 6-8