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The given graph is a displacement-time (D-T) graph, where the horizontal axis represents time \( T \) in seconds (s), and the vertical axis represents displacement \( D \) in meters (m). Let's break down the graph and solve the problem step by step.

### Identifying the Areas of Motion:
1. **From \( T = 0 \) to \( T = 2 \) seconds:**
   - The line is increasing linearly, which means there is motion, and the object is moving at a constant velocity. The slope of the line in this section represents the velocity.
   
2. **From \( T = 2 \) to \( T = 3 \) seconds:**
   - The line becomes flat (horizontal), indicating no change in displacement. This means there is **no motion** during this interval, and the object is at rest.

### Calculating the Velocity:
The velocity is given by the slope of the line during the motion phase (\( T = 0 \) to \( T = 2 \) s). The slope is calculated as:
\[
\text{Velocity} = \frac{\Delta D}{\Delta T} = \frac{D_2 - D_1}{T_2 - T_1}
\]
Where:
- \( D_2 = 2 \, \text{m} \) (final displacement at \( T = 2 \, \text{s} \))
- \( D_1 = 0 \, \text{m} \) (initial displacement at \( T = 0 \, \text{s} \))
- \( T_2 = 2 \, \text{s} \), \( T_1 = 0 \, \text{s} \)

So,
\[
\text{Velocity} = \frac{2 - 0}{2 - 0} = \frac{2}{2} = 1 \, \text{m/s}
\]

### Conclusion:
- The object moves with a constant velocity of **1 m/s** from \( T = 0 \) to \( T = 2 \) seconds.
- From \( T = 2 \) to \( T = 3 \) seconds, the object is stationary (no motion).

Would you like further details or have any questions? Here are five related questions:

1. How would the velocity change if the slope of the line were steeper?
2. Can we calculate acceleration from this graph? Why or why not?
3. What would the graph look like if the object was moving at a decreasing speed?
4. How does a velocity-time (V-T) graph differ from a displacement-time (D-T) graph?
5. If the object started moving backward after \( T = 2 \) seconds, how would the graph change?

**Tip:** The slope of a displacement-time graph gives you the velocity, and the steeper the slope, the faster the object is moving.

Identify(label) the areas of motion (or no motion). If motion is present, calculate the velocity.

Learn how to interpret displacement-time (D-T) graphs and calculate velocity. This problem focuses on identifying areas of motion and rest, with a detailed step-by-step explanation of calculating constant velocity using the formula Velocity = ΔD / ΔT. Suitable for students in Grades 8-10.

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