Math Problem Statement

                 x

15     

22     

34     

40     

P(X = x)

0.18     

0.30     

0.29     

0.23          a.

Is this a valid probability distribution?       multiple choice

Yes

No     Round answers to two decimal places.   b.

What is the probability that the random variable X is less than 35?      Probability      c.

What is the probability that the random variable X is between 13 and 28?      Probability      d.

What is the probability that the random variable X is greater than 21?      Probability   

Solution

Part (a): Is this a valid probability distribution?

A probability distribution is valid if the sum of the probabilities equals 1 and all probabilities are between 0 and 1.

Given probabilities:

P(X=15)=0.18,P(X=22)=0.30,P(X=34)=0.29,P(X=40)=0.23P(X = 15) = 0.18, \quad P(X = 22) = 0.30, \quad P(X = 34) = 0.29, \quad P(X = 40) = 0.23

Sum of the probabilities:

0.18+0.30+0.29+0.23=1.000.18 + 0.30 + 0.29 + 0.23 = 1.00

Since the sum is exactly 1 and all probabilities are between 0 and 1, this is a valid probability distribution.

The correct answer to part (a) is Yes.


Part (b): Probability that XX is less than 35

We are looking for P(X<35)P(X < 35), which means summing the probabilities for X=15X = 15 and X=22X = 22:

P(X<35)=P(X=15)+P(X=22)=0.18+0.30=0.48P(X < 35) = P(X = 15) + P(X = 22) = 0.18 + 0.30 = 0.48

The probability that XX is less than 35 is 0.48.


Part (c): Probability that XX is between 13 and 28

We are looking for P(13<X<28)P(13 < X < 28), which is the probability for X=15X = 15 and X=22X = 22:

P(13<X<28)=P(X=15)+P(X=22)=0.18+0.30=0.48P(13 < X < 28) = P(X = 15) + P(X = 22) = 0.18 + 0.30 = 0.48

The probability that XX is between 13 and 28 is 0.48.


Part (d): Probability that XX is greater than 21

We are looking for P(X>21)P(X > 21), which means summing the probabilities for X=22X = 22, X=34X = 34, and X=40X = 40:

P(X>21)=P(X=22)+P(X=34)+P(X=40)=0.30+0.29+0.23=0.82P(X > 21) = P(X = 22) + P(X = 34) + P(X = 40) = 0.30 + 0.29 + 0.23 = 0.82

The probability that XX is greater than 21 is 0.82.


Do you want more details on any part of this? Here are some follow-up questions:

  1. What properties define a valid probability distribution?
  2. How would the solution change if the sum of probabilities exceeded 1?
  3. How would you calculate probabilities for a continuous random variable?
  4. What other types of probability distributions are there besides discrete?
  5. How do we calculate probabilities when the distribution isn't uniform?

Tip: Always check that the sum of probabilities equals 1 when working with discrete probability distributions!

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Math Problem Analysis

Mathematical Concepts

Probability
Discrete Probability Distribution

Formulas

Sum of probabilities P(X=x) must equal 1
P(a < X < b) = P(X = a) + P(X = b) for discrete distributions

Theorems

Law of Total Probability

Suitable Grade Level

Grades 9-12