Math Problem Statement

Use the contour diagram for f(x, y) shown below to estimate the directional derivative of f in the direction \( \vec{v} \) at the point P.

Solution

In the image, the question asks for the estimation of the directional derivative of a function f(x,y)f(x, y) at various points using a contour diagram. Here are the specific cases mentioned:

  1. Part (a):

    • Point: P=(2,2)P = (2, 2)
    • Direction: v=i^\vec{v} = \hat{i} (along the positive xx-axis)
    • Directional derivative: Approximately 2
  2. Part (b):

    • Point: P=(3,2)P = (3, 2)
    • Direction: v=i^\vec{v} = -\hat{i} (along the negative xx-axis)
    • Directional derivative: Approximately −4
  3. Part (c):

    • Point: P=(4,1)P = (4, 1)
    • Direction: v=i^+j^2\vec{v} = \frac{\hat{i} + \hat{j}}{\sqrt{2}} (this direction is a unit vector at a 45° angle to the positive xx- and yy-axes)
    • Directional derivative: Approximately 6
  4. Part (d):

    • Point: P=(4,0)P = (4, 0)
    • Direction: v=i^\vec{v} = -\hat{i} (along the negative xx-axis)
    • Directional derivative: Approximately −5

These directional derivatives are estimated using the slope of the contour lines in the respective directions at the given points.

Would you like further clarification on how directional derivatives are computed or more details on contour lines?

Here are some related questions to explore:

  1. How is the gradient vector related to the directional derivative?
  2. Why is the direction v\vec{v} normalized in part (c)?
  3. How would the directional derivative change if the direction was reversed?
  4. What is the significance of the sign of the directional derivative?
  5. How do contour lines indicate the steepness of a function at a point?

Tip: The magnitude of the directional derivative indicates the rate of change of the function in that direction, while its sign shows whether the function is increasing or decreasing.

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Math Problem Analysis

Mathematical Concepts

Directional Derivative
Gradient
Contour Diagrams

Formulas

Directional Derivative = ∇f · \( \vec{v} \)
Gradient ∇f = \( \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \)

Theorems

Directional Derivative Theorem
Gradient and Directional Derivative Relationship

Suitable Grade Level

College level calculus or advanced high school mathematics (Grades 11-12)