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The problem states that \( y \) is directly proportional to \( x \), and we are given that \( y = 9 \) when \( x = 63 \). 

In mathematical terms, direct proportionality is written as:

\[
y = kx
\]

where \( k \) is the constant of proportionality. To find \( k \), we use the given values \( y = 9 \) and \( x = 63 \):

\[
9 = k \times 63
\]

Solving for \( k \):

\[
k = \frac{9}{63} = \frac{1}{7}
\]

Thus, the formula describing the situation is:

\[
y = \frac{1}{7}x
\]

Let me know if you'd like more details or further questions!

Here are 5 related questions:
1. What happens to \( y \) when \( x \) doubles in this formula?
2. How would the formula change if \( y \) was inversely proportional to \( x \)?
3. If \( x = 49 \), what is the value of \( y \)?
4. How would you express this relationship graphically?
5. What is the significance of the constant \( k \) in proportional relationships?

**Tip:** For direct proportionality, as one variable increases, the other increases at a constant rate.

y is directly proportional to x, and y is 9 when x is 63.

Learn how to describe a direct proportionality relationship using a formula. In this problem, y is directly proportional to x, with y = 9 when x = 63. Understand how to find the constant of proportionality and express the relationship in the form y = kx.

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