The value of *y* is directly proportional to the value of *x*. When *x* = 512, *y* = 128.

What is the value of *y* when *x* = 64?

A.16

B.8

C.256

D.32


The problem states that *y* is directly proportional to *x*, meaning:

\[
y = kx
\]

Where *k* is the constant of proportionality. From the given information, when *x* = 512, *y* = 128. Substituting these values into the equation to solve for *k*:

\[
128 = k \times 512
\]

Solving for *k*:

\[
k = \frac{128}{512} = \frac{1}{4}
\]

Now that we know *k*, we can use it to find the value of *y* when *x* = 64:

\[
y = \frac{1}{4} \times 64 = 16
\]

Therefore, the value of *y* when *x* = 64 is:

\[
\boxed{16}
\]

Would you like further details on direct proportionality?

Here are 5 related questions for further practice:
1. What is the formula for inverse proportionality?
2. If *x* is directly proportional to *y* and *x* = 100, *y* = 50, what is the value of *y* when *x* = 20?
3. How do you interpret a graph of a direct proportion?
4. What happens to *y* if *x* is doubled in a direct proportional relationship?
5. Can direct proportionality exist if one of the variables is negative?

**Tip:** In direct proportionality, as one variable increases, the other increases at a constant rate.

The value of *y* is directly proportional to the value of *x*. When *x* = 512, *y* = 128. What is the value of *y* when *x* = 64? A.16 B.8 C.256 D.32

Solve a direct proportionality problem where *y* is directly proportional to *x*. When *x* = 512, *y* = 128. Learn how to find the value of *y* when *x* = 64 using algebraic formulas. Suitable for Grades 6-8 students.

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