Math Problem Statement

The value of y is directly proportional to the value of x. When x = 512, y = 128. What is the value of y when x = 64?

Solution

The problem states that yy is directly proportional to xx, meaning that:

y=kxy = kx

where kk is the constant of proportionality.

We are given that when x=512x = 512, y=128y = 128. Using this information, we can find kk:

128=k512128 = k \cdot 512

Solving for kk:

k=128512=14k = \frac{128}{512} = \frac{1}{4}

Now, we can use this constant to find yy when x=64x = 64:

y=1464=16y = \frac{1}{4} \cdot 64 = 16

Therefore, the value of yy when x=64x = 64 is 16\boxed{16}, which corresponds to option C.


Do you need more details or have any further questions?

Here are 5 related questions to explore further:

  1. How would the relationship change if yy were inversely proportional to xx?
  2. What happens to the value of yy if xx is doubled in a directly proportional relationship?
  3. How can you find the proportionality constant if only the ratio between xx and yy is given?
  4. Can you determine the value of xx if yy is known and kk is already calculated?
  5. How does a proportional relationship compare to a linear relationship?

Tip: In direct proportionality, the ratio between two variables remains constant, making it easy to scale values up or down once the constant is known.

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Math Problem Analysis

Mathematical Concepts

Proportions
Direct Variation

Formulas

y = kx

Theorems

Proportionality Theorem

Suitable Grade Level

Grades 7-9