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The problem describes a directly proportional relationship between the number of track practices Craig attends (denoted as \(x\)) and the distance he runs (denoted as \(y\)).

The table provides the following values:
- When \(x = 4\), \(y = 12\)
- When \(x = 5\), \(y = 15\)
- When \(x = 6\), \(y = 18\)

Since the relationship is directly proportional, we know that:
\[
y = kx
\]
where \(k\) is the constant of proportionality.

Let's calculate \(k\) using the data from the table. For \(x = 4\) and \(y = 12\):
\[
k = \frac{y}{x} = \frac{12}{4} = 3
\]

So, the relationship between \(x\) and \(y\) is:
\[
y = 3x
\]

Now, we can find the distance Craig runs if he attends 9 track practices by substituting \(x = 9\) into the equation:
\[
y = 3(9) = 27
\]

Thus, Craig will run 27 miles if he attends 9 track practices.

Would you like more details on this? Here are some related questions you could explore:

1. What would the distance be if Craig attended 8 track practices?
2. How would the equation change if the proportionality constant was 4 instead of 3?
3. Can you express this proportional relationship as a ratio and solve using ratios?
4. How can you graph this relationship between the number of practices and distance?
5. What is the interpretation of the constant of proportionality in this context?

**Tip:** In directly proportional relationships, the ratio of the two variables remains constant, which is useful for solving missing values quickly!

What is the distance Craig runs if he attends 9 track practices?

Understand how to calculate the distance Craig runs if he attends 9 track practices using the concept of direct proportion. Learn how to find the proportionality constant and use it to solve real-world problems. Suitable for Grade 7 students.

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