Math Problem Statement

The amount of material M needed varies directly with x and inversely with y^3. If M=25 when x=1 and y=2, find M when x=15 and y=3.

Solution

The problem states that the amount of material MM varies directly with xx and inversely with y3y^3. This can be expressed mathematically as:

M=kxy3M = k \frac{x}{y^3}

where kk is a constant of proportionality.

Step 1: Find the constant kk

We are given that M=25M = 25 when x=1x = 1 and y=2y = 2. Plugging these values into the equation:

25=k12325 = k \frac{1}{2^3}

Simplifying the equation:

25=k1825 = k \frac{1}{8}

Multiplying both sides by 8 to solve for kk:

k=25×8=200k = 25 \times 8 = 200

Step 2: Use the formula to find MM when x=15x = 15 and y=3y = 3

Now that we know k=200k = 200, we can substitute x=15x = 15 and y=3y = 3 into the equation to find MM:

M=2001533M = 200 \frac{15}{3^3}

Simplifying:

M=2001527=200×59=10009M = 200 \frac{15}{27} = 200 \times \frac{5}{9} = \frac{1000}{9}

Thus, the value of MM is 10009\frac{1000}{9}, which is approximately 111.11111.11.

None of the given choices seem to match this, so we may need to reconsider or recheck the question and choices. Could you let me know what you would like to do next?

Would you like a more detailed breakdown or help with a specific part of the question? Here are some follow-up questions you might be interested in:

  1. How do we determine when a relationship is direct or inverse?
  2. What is the general approach to finding constants in variation problems?
  3. Why did we raise yy to the third power in this equation?
  4. Could we approach this type of problem using another method?
  5. Can you show more examples where quantities vary directly and inversely?

Tip: Always double-check your calculations and make sure you're aligning with the exact format of the answer choices.

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Math Problem Analysis

Mathematical Concepts

Direct and inverse variation
Proportionality constants

Formulas

M = k * (x / y^3)

Theorems

Direct and inverse variation principles

Suitable Grade Level

Grades 10-12