How much 0.1 M **Celsius** solution can be made by diluting 300 mL of 5 M **Celsius**?

To determine how much 0.1 M solution can be made by diluting a 5 M solution, we can use the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

where:
- \( C_1 \) is the initial concentration (5 M),
- \( V_1 \) is the initial volume (300 mL),
- \( C_2 \) is the final concentration (0.1 M),
- \( V_2 \) is the final volume we want to find.

### Step-by-Step Solution

1. Substitute the values into the equation:
   \[
   (5 \, \text{M}) \times (300 \, \text{mL}) = (0.1 \, \text{M}) \times V_2
   \]

2. Multiply the initial concentration and initial volume:
   \[
   1500 = 0.1 \times V_2
   \]

3. Solve for \( V_2 \) by dividing both sides by 0.1:
   \[
   V_2 = \frac{1500}{0.1} = 15000 \, \text{mL}
   \]

### Conclusion

You can make **15,000 mL** (or 15 liters) of 0.1 M solution by diluting 300 mL of a 5 M solution.

Would you like further details or have any questions?

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Here are 5 related questions for further exploration:

1. How would the final volume change if the initial concentration were 2 M instead of 5 M?
2. What volume of a 10 M solution would be needed to make the same 0.1 M solution?
3. If you only had 100 mL of 5 M solution, what final concentration could you achieve by diluting to 1500 mL?
4. How can you calculate the dilution factor needed for any concentration change?
5. What are practical applications of solution dilutions in chemistry?

**Tip:** Remember that dilution calculations always involve keeping the number of moles constant between the concentrated and diluted solutions.

How much 0.1 M Celsius solution can be made by diluting 300 mL of 5 M Celsius?

Learn how to dilute a 5 M Celsius solution to a 0.1 M concentration. By applying the dilution formula, you can calculate that 300 mL of 5 M solution will produce 15,000 mL (15 liters) of 0.1 M solution. Suitable for high school chemistry students.

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