How much 0.1 M **Celsius** solution can be made by diluting 300 mL of 5 M **Celsius**?

To solve this problem, we'll use the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

where:
- \( C_1 \) is the initial concentration (5 M),
- \( V_1 \) is the initial volume (300 mL),
- \( C_2 \) is the final concentration (0.1 M),
- \( V_2 \) is the final volume, which we are trying to find.

### Step 1: Plug in the values

\[
5 \, \text{M} \times 300 \, \text{mL} = 0.1 \, \text{M} \times V_2
\]

### Step 2: Solve for \( V_2 \)

\[
V_2 = \frac{5 \times 300}{0.1}
\]

Calculating this gives:

\[
V_2 = \frac{1500}{0.1} = 15000 \, \text{mL}
\]

### Final Answer
You can make **15,000 mL** (or 15 L) of a 0.1 M solution by diluting 300 mL of a 5 M solution.

Would you like further details or have any questions?

Here are five related questions you might explore:
1. How would the final volume change if the initial concentration were 10 M instead of 5 M?
2. How much solvent (e.g., water) is needed to achieve this dilution?
3. How does this calculation change if we have different units for volume, such as liters?
4. What is the impact of temperature on the concentration of solutions, if any?
5. Can this dilution method be applied to non-aqueous solutions?

**Tip:** Always double-check the units you’re working with when doing dilutions to avoid confusion between mL and L.

How much 0.1 M Celsius solution can be made by diluting 300 mL of 5 M Celsius?

Learn how to calculate the final volume when diluting a 5 M Celsius solution to create 0.1 M Celsius solution. The solution explains the dilution formula and provides a step-by-step approach. Suitable for students in Grades 9-11.

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