Math Problem Statement

UV is dilated by a scale factor of 22 to form start overline, U, prime, V, prime, end overline U ′ V ′

. start overline, U, V, end overline UV measures 66. What is the measure of start overline, U, prime, V, prime, end overline U ′ V ′

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Solution

Given that segment UVUV is dilated by a scale factor of 22 to form segment UVU'V', and the length of UVUV is 66, we need to find the length of UVU'V'.

The relationship between the original segment UVUV and the dilated segment UVU'V' is given by the formula:

UV=scale factor×UVU'V' = \text{scale factor} \times UV

Substituting the given values:

UV=22×66=1452U'V' = 22 \times 66 = 1452

So, the length of UVU'V' is 1452 units.

Would you like more details or have any questions?

Here are some related questions:

  1. What is dilation in geometry?
  2. How does the scale factor affect the size of a figure?
  3. Can dilation result in a smaller figure, and how?
  4. What are some real-world applications of dilation?
  5. How do you find the center of dilation?

Tip: When working with dilations, always remember that a scale factor greater than 1 enlarges the figure, while a scale factor between 0 and 1 reduces it.

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Math Problem Analysis

Mathematical Concepts

Geometry
Dilation
Scale Factor

Formulas

U'V' = Scale Factor × UV

Theorems

Dilation Theorem

Suitable Grade Level

Grades 7-8