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The problem involves a dilation of a rectangle by a scale factor of 6, and you're asked to find the area of the dilated rectangle, given that the original area is 3 square inches.

### Key concepts:
- **Dilation** changes the size of a figure by a specific scale factor, but the shape remains similar.
- When a figure is dilated, **the area is multiplied by the square of the scale factor**.

### Given:
- The original area of rectangle \( WXYZ \) is 3 square inches.
- The scale factor for the dilation is 6.

### To find:
- The area of the dilated rectangle \( W'X'Y'Z' \).

The area of the dilated rectangle is calculated by multiplying the original area by the square of the scale factor:

\[
\text{New Area} = (\text{Scale Factor})^2 \times \text{Original Area}
\]
\[
\text{New Area} = 6^2 \times 3 = 36 \times 3 = 108 \text{ square inches}
\]

Thus, the area of the dilated rectangle is **108 square inches**, which corresponds to option B.

Would you like further explanation, or do you have any other questions? Here are some related questions:

1. What happens to the perimeter of a shape when it is dilated?
2. How does dilation affect the dimensions (length and width) of a rectangle?
3. Can dilation change the shape of a figure, or just its size?
4. How would you find the area of a figure dilated by a fractional scale factor?
5. What is the relationship between the scale factor and the volume of a 3D object?

**Tip**: When dealing with dilation and area, always remember to square the scale factor to determine the new area.

Rectangle WXYZ is dilated by a scale factor of 6 to create rectangle W'X'Y'Z'. If the area of rectangle WXYZ is 3 square inches, what is the area of rectangle W'X'Y'Z'?

Find the area of a rectangle dilated by a scale factor of 6. Given the original area is 3 square inches, this geometry problem explores dilation, scale factor, and area calculations. Suitable for students in Grades 6-8.

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