Math Problem Statement

f(x) = 3x^9

Solution

Given the function f(x)=3x9f(x) = 3x^9, we can analyze and perform a variety of tasks such as differentiation, integration, and general analysis. Let me start by providing the derivative and integral of the function:

1. Derivative of f(x)f(x)

To differentiate f(x)=3x9f(x) = 3x^9 with respect to xx, apply the power rule:

f(x)=ddx[3x9]=93x91=27x8f'(x) = \frac{d}{dx}[3x^9] = 9 \cdot 3x^{9-1} = 27x^8

So, the derivative of the function is:

f(x)=27x8f'(x) = 27x^8

2. Integral of f(x)f(x)

To find the indefinite integral of f(x)=3x9f(x) = 3x^9, apply the power rule of integration:

3x9dx=3x9+19+1+C=3x1010+C=310x10+C\int 3x^9 \, dx = \frac{3x^{9+1}}{9+1} + C = \frac{3x^{10}}{10} + C = \frac{3}{10}x^{10} + C

Thus, the indefinite integral is:

f(x)dx=310x10+C\int f(x) \, dx = \frac{3}{10}x^{10} + C

Do you have any specific questions or would you like further details on these calculations?

Related Questions:

  1. What is the second derivative of f(x)=3x9f(x) = 3x^9?
  2. How would you find the critical points of the function f(x)f(x)?
  3. What is the definite integral of f(x)f(x) over a specific interval, say from x=0x=0 to x=2x=2?
  4. How does the graph of f(x)=3x9f(x) = 3x^9 behave as xx \to \infty and xx \to -\infty?
  5. Can you solve for xx when f(x)=0f(x) = 0?

Tip:

When differentiating or integrating powers of xx, always remember to apply the power rule carefully, adjusting the exponent accordingly.

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Integration
Polynomial Functions

Formulas

Power Rule for Differentiation: d/dx[x^n] = nx^(n-1)
Power Rule for Integration: ∫x^n dx = (x^(n+1))/(n+1) + C

Theorems

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Suitable Grade Level

Grades 11-12 (or early university level)