Math Problem Statement

y=1/(5x+2)^3 dy/dx

Solution

To find the derivative of the function y=1(5x+2)3y = \frac{1}{(5x + 2)^3}, we can apply the chain rule.

Step 1: Rewrite the function

First, rewrite the function as a power function: y=(5x+2)3y = (5x + 2)^{-3}

Step 2: Apply the chain rule

The chain rule states that if y=[u(x)]ny = [u(x)]^n, then: dydx=n[u(x)]n1dudx\frac{dy}{dx} = n \cdot [u(x)]^{n-1} \cdot \frac{du}{dx} In this case, u(x)=5x+2u(x) = 5x + 2 and n=3n = -3.

Step 3: Differentiate

  1. Differentiate the outer function: dydu=3(5x+2)4\frac{dy}{du} = -3 \cdot (5x + 2)^{-4}
  2. Differentiate the inner function u(x)=5x+2u(x) = 5x + 2: dudx=5\frac{du}{dx} = 5

Step 4: Combine the results

Now, multiply these results to get the derivative: dydx=3(5x+2)45\frac{dy}{dx} = -3 \cdot (5x + 2)^{-4} \cdot 5

Final Answer

dydx=15(5x+2)4\frac{dy}{dx} = -15 \cdot (5x + 2)^{-4} Or equivalently: dydx=15(5x+2)4\frac{dy}{dx} = \frac{-15}{(5x + 2)^4}

Would you like more details or have any questions?


Here are 5 related questions you might find interesting:

  1. What is the derivative of y=1(3x+1)2y = \frac{1}{(3x + 1)^2}?
  2. How does the chain rule apply to trigonometric functions?
  3. Can you find the second derivative of y=1(5x+2)3y = \frac{1}{(5x + 2)^3}?
  4. What is the integral of y=(5x+2)3y = (5x + 2)^{-3}?
  5. How would the derivative change if y=1(5x2+2)3y = \frac{1}{(5x^2 + 2)^3}?

Tip: When differentiating composite functions, always identify the outer and inner functions before applying the chain rule.

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Chain Rule

Formulas

Chain rule: dy/dx = n * [u(x)]^(n-1) * du/dx
Power rule: d/dx [u(x)]^n = n * [u(x)]^(n-1)

Theorems

Chain Rule

Suitable Grade Level

Grades 11-12