Math Problem Statement

differentiate using the chain rule and showing all working step by step, (x-3)^5

Solution

To differentiate the function (x3)5(x - 3)^5 using the chain rule, let's proceed step-by-step:

Step 1: Identify the Outer and Inner Functions

The given function is (x3)5(x - 3)^5.

  • Outer function: u5u^5, where u=(x3)u = (x - 3)
  • Inner function: u=(x3)u = (x - 3)

Step 2: Differentiate the Outer Function

Using the chain rule formula, which is:

ddx[f(g(x))]=f(g(x))g(x)\frac{d}{dx} \left[f(g(x))\right] = f'(g(x)) \cdot g'(x)

Let’s differentiate the outer function u5u^5 with respect to uu:

ddu(u5)=5u4\frac{d}{du}(u^5) = 5u^4

Step 3: Differentiate the Inner Function

Now, differentiate the inner function u=(x3)u = (x - 3) with respect to xx:

ddx(x3)=1\frac{d}{dx}(x - 3) = 1

Step 4: Apply the Chain Rule

Combine the derivatives of the outer and inner functions:

ddx[(x3)5]=5(x3)41\frac{d}{dx}\left[(x - 3)^5\right] = 5(x - 3)^4 \cdot 1

Step 5: Simplify the Expression

The derivative simplifies to:

ddx[(x3)5]=5(x3)4\frac{d}{dx}\left[(x - 3)^5\right] = 5(x - 3)^4

Final Answer:

ddx[(x3)5]=5(x3)4\frac{d}{dx}\left[(x - 3)^5\right] = 5(x - 3)^4

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

  1. How do you differentiate a function with multiple nested functions using the chain rule?
  2. What is the chain rule and when is it applicable?
  3. How would you differentiate (2x+1)3(2x + 1)^3 using the chain rule?
  4. Can you explain how the power rule and chain rule work together in this example?
  5. What happens if we differentiate (x3)5(x - 3)^5 using the product rule instead of the chain rule?

Tip: When using the chain rule, always identify the outer and inner functions first, as it simplifies the differentiation process.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Chain Rule
Power Rule

Formulas

Chain rule: d/dx[f(g(x))] = f'(g(x)) * g'(x)
Power rule: d/du(u^n) = n * u^(n-1)

Theorems

Chain Rule
Power Rule

Suitable Grade Level

Grades 11-12