Math Problem Statement

Differentiate the function g\left(x\right)+=e^{x+2} $$$$ +2.

Solution

It seems like there might be a small error in your function notation. Based on what you've provided, I assume you're asking to differentiate the function:

g(x)=ex+2+2g(x) = e^{x+2} + 2

Let's differentiate this with respect to xx.

Steps:

  1. The derivative of ex+2e^{x+2} with respect to xx is simply ex+2e^{x+2}, because the exponential function's derivative is the same as the function itself.
  2. The derivative of the constant 22 is 00, as constants have a zero derivative.

Solution:

g(x)=ddx(ex+2+2)=ex+2+0=ex+2g'(x) = \frac{d}{dx}\left(e^{x+2} + 2\right) = e^{x+2} + 0 = e^{x+2}

Thus, the derivative is:

g(x)=ex+2g'(x) = e^{x+2}

Would you like any further details or have any questions?


Here are 5 related questions for you to explore:

  1. How do you differentiate a function with multiple terms, like polynomials?
  2. What is the derivative of a function involving ln(x)\ln(x)?
  3. How does the chain rule apply to more complex exponentials, such as ef(x)e^{f(x)}?
  4. How would you find the second derivative of g(x)g(x)?
  5. What happens if you differentiate a product of functions?

Tip: When differentiating exponentials, always watch out for whether a chain rule is necessary if the exponent is more complex than a linear function of xx.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Exponential Functions

Formulas

Derivative of exponential function

Theorems

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Suitable Grade Level

Advanced High School