Math Problem Statement

d-dx(cosec)

Solution

To differentiate the cosecant function (csc(x)\csc(x)) with respect to xx, we use the following derivative formula:

ddx(csc(x))=csc(x)cot(x)\frac{d}{dx}(\csc(x)) = -\csc(x) \cot(x)

So, the derivative of csc(x)\csc(x) with respect to xx is:

ddx(csc(x))=csc(x)cot(x)\frac{d}{dx}(\csc(x)) = -\csc(x) \cot(x)

This result comes from using the chain rule and the basic trigonometric identities.

Would you like more details on the derivation? Here are some related questions to explore:

  1. What is the derivative of sec(x)\sec(x)?
  2. How is the derivative of cot(x)\cot(x) derived?
  3. What are the basic trigonometric identities used in differentiation?
  4. How do you apply the chain rule in trigonometric differentiation?
  5. What is the significance of the negative sign in the derivative of csc(x)\csc(x)?

Tip: When differentiating trigonometric functions, it's helpful to remember their basic identities and derivatives.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Differentiation
Trigonometric Identities

Formulas

\( \frac{d}{dx}(\csc(x)) = -\csc(x) \cot(x) \)

Theorems

-

Suitable Grade Level

Advanced High School