Math Problem Statement

Form a differential equation corresponding to x^2 + y^2 + 2ax + 2by + c = 0 by eliminating a, b, c.

Solution

The problem asks to form a differential equation corresponding to the equation:

x2+y2+2ax+2by+c=0x^2 + y^2 + 2ax + 2by + c = 0

by eliminating the parameters aa, bb, and cc.

Steps to Solve:

  1. Differentiate with respect to xx:
    • Implicitly differentiate the equation with respect to xx, treating yy as a function of xx.

ddx(x2+y2+2ax+2by+c)=0\frac{d}{dx}\left( x^2 + y^2 + 2ax + 2by + c \right) = 0

This gives:

2x+2ydydx+2a+2bdydx=02x + 2y\frac{dy}{dx} + 2a + 2b\frac{dy}{dx} = 0

Simplifying:

x+ydydx+a+bdydx=0(Equation 1)x + y\frac{dy}{dx} + a + b\frac{dy}{dx} = 0 \quad \text{(Equation 1)}

  1. Differentiate again with respect to xx to get rid of aa and bb:

Differentiate the result of the first derivative:

ddx(x+ydydx+a+bdydx)=0\frac{d}{dx}\left( x + y\frac{dy}{dx} + a + b\frac{dy}{dx} \right) = 0

Expanding this:

1+dydx+yd2ydx2+a+bdydx+bd2ydx2=01 + \frac{dy}{dx} + y\frac{d^2y}{dx^2} + a' + b'\frac{dy}{dx} + b\frac{d^2y}{dx^2} = 0

Now, use these two equations to eliminate the parameters aa, bb, and cc, leading to the desired differential equation.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Implicit Differentiation
Elimination of Parameters

Formulas

Implicit differentiation: d/dx [x^2 + y^2 + 2ax + 2by + c] = 0
First derivative: x + y(dy/dx) + a + b(dy/dx) = 0

Theorems

Rules of Differentiation

Suitable Grade Level

University level, Calculus