Math Problem Statement

Find a differential equation whose solution x ^ 2 + y ^ 2 - 2Ax - 2By + C = 0 Where A, B, C arbitrary constants and A ^ 2 + B ^ 2 > C

Solution

To find a differential equation whose solution is given by:

x2+y22Ax2By+C=0,x^2 + y^2 - 2Ax - 2By + C = 0,

we can proceed by differentiating this implicit equation with respect to xx and then eliminate the constants AA, BB, and CC to obtain a differential equation in terms of xx, yy, and dydx\frac{dy}{dx}.

Step 1: Differentiate with respect to xx

The given equation is: x2+y22Ax2By+C=0.x^2 + y^2 - 2Ax - 2By + C = 0.

Differentiating with respect to xx, we obtain: 2x+2ydydx2A2Bdydx=0.2x + 2y \frac{dy}{dx} - 2A - 2B \frac{dy}{dx} = 0.

Simplify this to: (xA)+(yB)dydx=0.(x - A) + (y - B) \frac{dy}{dx} = 0.

Step 2: Differentiate again to eliminate AA and BB

Now, differentiate once more with respect to xx: 1+dydxdydx+(yB)d2ydx2=0.1 + \frac{dy}{dx} \cdot \frac{dy}{dx} + (y - B) \frac{d^2y}{dx^2} = 0.

This becomes: 1+(dydx)2+(yB)d2ydx2=0.1 + \left( \frac{dy}{dx} \right)^2 + (y - B) \frac{d^2y}{dx^2} = 0.

Since BB was arbitrary, express BB in terms of xx, yy, and their derivatives to obtain the final differential equation

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Implicit Differentiation
Multivariable Calculus

Formulas

Implicit differentiation formula: \( \frac{d}{dx}f(x, y) = f_x + f_y \frac{dy}{dx} \)
Differential equation solution: \( x^2 + y^2 - 2Ax - 2By + C = 0 \)

Theorems

Implicit Function Theorem

Suitable Grade Level

College Level or Advanced High School Calculus