Math Problem Statement

Alice owes Greg 500 dollars. She has in her wallet twenty 10-dollar notes, two 50-dollar notes, and ten 100-dollar notes. How many different ways are there for Alice to repay Greg?

Solution

Alice owes Greg 500 dollars, and she has a set of bills consisting of:

  • 20 ten-dollar notes
  • 2 fifty-dollar notes
  • 10 one-hundred-dollar notes

We need to determine how many different ways Alice can use these notes to repay Greg exactly 500 dollars.

Approach:

Let x1x_1, x2x_2, and x3x_3 represent the number of 10-dollar, 50-dollar, and 100-dollar notes, respectively, that Alice uses. The total sum equation is:

10x1+50x2+100x3=50010x_1 + 50x_2 + 100x_3 = 500

Where:

  • x1x_1 is between 0 and 20 (inclusive),
  • x2x_2 is between 0 and 2 (inclusive),
  • x3x_3 is between 0 and 5 (inclusive).

Steps:

  1. First, express x1x_1 in terms of x2x_2 and x3x_3: x1=50050x2100x310x_1 = \frac{500 - 50x_2 - 100x_3}{10} For x1x_1 to be valid, 50050x2100x3500 - 50x_2 - 100x_3 must be divisible by 10, and x1x_1 must be within its allowed range 0x1200 \leq x_1 \leq 20.

  2. We will iterate through all possible values of x2x_2 and x3x_3, checking the corresponding value of x1x_1.

Solution:

Let’s calculate how many ways Alice can repay Greg by systematically checking each possibility.There are 8 different ways Alice can repay Greg exactly 500 dollars using her available notes.

Would you like further details or have any questions?

Here are 5 related questions to expand on this topic:

  1. What would change if Alice had fewer 100-dollar notes?
  2. How would the number of ways change if Alice owed 600 dollars instead of 500?
  3. What if Alice only had 50-dollar and 100-dollar notes—how many ways could she repay 500 dollars?
  4. How would the solution change if Alice had an unlimited number of each note?
  5. Could this problem be solved using combinatorics, and how?

Tip: In problems like these, breaking down the total sum into combinations of smaller denominations helps simplify the solution.

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Math Problem Analysis

Mathematical Concepts

Algebra
Combinatorics
Diophantine Equations

Formulas

10x1 + 50x2 + 100x3 = 500
x1 = (500 - 50x2 - 100x3) / 10

Theorems

Diophantine equation solutions

Suitable Grade Level

Grades 9-12