Let the number of five-dollar bills be $x$ and the number of ten-dollar bills be $y$.

We are given two pieces of information:

1. The total number of bills is 121: $x + y = 121$

2. The total value of the money is $935: $5x + 10y = 935$

We can solve this system of equations to find $y$.

Step 1: Solve the first equation for $x$

From $x + y = 121$, we can express $x$ as: $x = 121 - y$

Step 2: Substitute $x = 121 - y$ into the second equation

Substitute $x = 121 - y$ into the equation $5x + 10y = 935$: $5(121 - y) + 10y = 935$

Step 3: Simplify and solve for $y$

Distribute the 5: $5 \times 121 - 5y + 10y = 935$ $605 - 5y + 10y = 935$ Combine like terms: $605 + 5y = 935$ Subtract 605 from both sides: $5y = 330$ Divide by 5: $y = 66$

Thus, the cashier has 66 ten-dollar bills.

Conclusion

The cashier has 66 ten-dollar bills.

Would you like further details or have any questions?

Here are 5 related questions for further practice:

1. How many five-dollar bills does the cashier have?
2. If the cashier had 150 bills, how would that affect the solution?
3. What if the total value of the money was $960 instead of $935?
4. If the cashier had 60 ten-dollar bills, how many five-dollar bills would they have?
5. How can you check if your solution to a system of equations is correct?

Tip: Always double-check your work by substituting your answers back into the original equations to verify that they satisfy both conditions.