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The question asks to determine how many of the 36 possible outcomes (when rolling two dice) result in a sum between 2 and 9, inclusive.

Let's analyze:

### Possible sums with two dice:
1. **Sum = 2**: (1,1)
2. **Sum = 3**: (1,2), (2,1)
3. **Sum = 4**: (1,3), (2,2), (3,1)
4. **Sum = 5**: (1,4), (2,3), (3,2), (4,1)
5. **Sum = 6**: (1,5), (2,4), (3,3), (4,2), (5,1)
6. **Sum = 7**: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)
7. **Sum = 8**: (2,6), (3,5), (4,4), (5,3), (6,2)
8. **Sum = 9**: (3,6), (4,5), (5,4), (6,3)

### Total favorable outcomes:
- Sum 2: 1 outcome
- Sum 3: 2 outcomes
- Sum 4: 3 outcomes
- Sum 5: 4 outcomes
- Sum 6: 5 outcomes
- Sum 7: 6 outcomes
- Sum 8: 5 outcomes
- Sum 9: 4 outcomes

Adding these, we get:
\[
1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 = 30
\]

Thus, **there are 30 different ways** the sum of the two dice can be between 2 and 9, inclusive.

Would you like further details or have any questions? Here are 5 related questions for you:

1. How many possible outcomes are there in total when rolling two dice?
2. What is the probability of getting a sum between 2 and 9?
3. What are the outcomes for a sum of exactly 10 or higher?
4. How do we calculate the total probability space for rolling two dice?
5. Can you list all outcomes that give an odd sum?

**Tip:** When calculating probabilities, always divide the favorable outcomes by the total number of possible outcomes to get a fraction.

Of the 36 possible outcomes, determine the number for which the sum (for both dice) is between 2 and 9.

Find out how many of the 36 possible outcomes when rolling two dice result in a sum between 2 and 9. This problem covers key probability concepts and is suitable for students in Grades 6-8.

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