Math Problem Statement
If a coin is tossed
10001000
times, we would expect approximately
500500
of the outcomes to be heads. It can be demonstrated that a coin is unfair if h, the number of outcomes that results in heads, satisfies
StartAbsoluteValue StartFraction h minus 500 Over 50 EndFraction EndAbsoluteValue greater than or equals 1.645h−50050≥1.645.
Describe the number of outcomes that result in heads that determine an unfair coin that is tossed
10001000
times.
Solution
To determine whether a coin is unfair based on the number of heads obtained after tossing the coin 1000 times, we are given the condition:
Where:
- is the number of heads obtained.
- 500 is the expected number of heads (since 1000 tosses would give 500 heads in a fair coin).
- 50 is the standard deviation in this case (since ).
Step-by-step approach:
-
Remove the absolute value: The inequality can be split into two cases:
-
Solve each case:
For the first case: Multiply both sides by 50: Add 500 to both sides: Since must be an integer, round it up:
For the second case: Multiply both sides by 50: Add 500 to both sides: Round it down:
Conclusion:
The number of outcomes that result in heads must either be greater than or equal to 583, or less than or equal to 417, for the coin to be considered unfair. In other words:
- If or , the coin is unfair.
Would you like further details or have any questions?
Here are 5 related questions to explore further:
- What is the meaning of the 1.645 value in this context?
- How would the inequality change if the number of tosses was 10,000 instead of 1,000?
- Can we interpret this result as a hypothesis test?
- What is the significance of the number 50 in this problem?
- How would we calculate the probability of getting 583 heads or more if the coin is fair?
Tip: In hypothesis testing, a value like 1.645 typically corresponds to a confidence level, here likely 90%, which helps to determine the threshold for fairness.
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Math Problem Analysis
Mathematical Concepts
Probability
Statistics
Inequality
Formulas
|(h - 500) / 50| ≥ 1.645
Standard Deviation for Binomial Distribution: σ = √(n * p * (1 - p))
Theorems
Normal Approximation to Binomial Distribution
Suitable Grade Level
Grades 10-12
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