Math Problem Statement

Which set of ordered pairs left parenthesis, x, comma, y, right parenthesis(x,y) could represent a linear function?

A, equals, left curly bracket, left parenthesis, minus, 6, comma, 0, right parenthesis, comma, left parenthesis, minus, 3, comma, 3, right parenthesis, comma, left parenthesis, 0, comma, 6, right parenthesis, comma, left parenthesis, 3, comma, 9, right parenthesis, right curly bracket

A=

{(−6,0),(−3,3),(0,6),(3,9)}

B, equals, left curly bracket, left parenthesis, minus, 6, comma, 5, right parenthesis, comma, left parenthesis, minus, 3, comma, 2, right parenthesis, comma, left parenthesis, 0, comma, minus, 2, right parenthesis, comma, left parenthesis, 3, comma, minus, 5, right parenthesis, right curly bracket

B=

{(−6,5),(−3,2),(0,−2),(3,−5)}

C, equals, left curly bracket, left parenthesis, 2, comma, 8, right parenthesis, comma, left parenthesis, 4, comma, 4, right parenthesis, comma, left parenthesis, 5, comma, 0, right parenthesis, comma, left parenthesis, 7, comma, minus, 8, right parenthesis, right curly bracket

C=

{(2,8),(4,4),(5,0),(7,−8)}

D, equals, left curly bracket, left parenthesis, minus, 4, comma, 5, right parenthesis, comma, left parenthesis, minus, 1, comma, 4, right parenthesis, comma, left parenthesis, 2, comma, 3, right parenthesis, comma, left parenthesis, 6, comma, 2, right parenthesis, right curly bracket

D=

{(−4,5),(−1,4),(2,3),(6,2)}

Solution

To determine which set of ordered pairs represents a linear function, we need to check whether the relationship between the xx-values and yy-values is consistent with a straight line. In other words, the change in yy with respect to xx should be constant across all pairs in the set.

Let's calculate the slope (change in yy over change in xx) for each set:

A: {(-6, 0), (-3, 3), (0, 6), (3, 9)}

For the points (6,0)(-6, 0) and (3,3)(-3, 3): slope=303(6)=33=1\text{slope} = \frac{3 - 0}{-3 - (-6)} = \frac{3}{3} = 1

For the points (3,3)(-3, 3) and (0,6)(0, 6): slope=630(3)=33=1\text{slope} = \frac{6 - 3}{0 - (-3)} = \frac{3}{3} = 1

For the points (0,6)(0, 6) and (3,9)(3, 9): slope=9630=33=1\text{slope} = \frac{9 - 6}{3 - 0} = \frac{3}{3} = 1

The slope is consistent (1) for all pairs in set A. Hence, A represents a linear function.

B: {(-6, 5), (-3, 2), (0, -2), (3, -5)}

For the points (6,5)(-6, 5) and (3,2)(-3, 2): slope=253(6)=33=1\text{slope} = \frac{2 - 5}{-3 - (-6)} = \frac{-3}{3} = -1

For the points (3,2)(-3, 2) and (0,2)(0, -2): slope=220(3)=431\text{slope} = \frac{-2 - 2}{0 - (-3)} = \frac{-4}{3} \neq -1

Since the slope is not constant, B does not represent a linear function.

C: {(2, 8), (4, 4), (5, 0), (7, -8)}

For the points (2,8)(2, 8) and (4,4)(4, 4): slope=4842=42=2\text{slope} = \frac{4 - 8}{4 - 2} = \frac{-4}{2} = -2

For the points (4,4)(4, 4) and (5,0)(5, 0): slope=0454=41=4\text{slope} = \frac{0 - 4}{5 - 4} = \frac{-4}{1} = -4

Since the slope is not constant, C does not represent a linear function.

D: {(-4, 5), (-1, 4), (2, 3), (6, 2)}

For the points (4,5)(-4, 5) and (1,4)(-1, 4): slope=451(4)=13=13\text{slope} = \frac{4 - 5}{-1 - (-4)} = \frac{-1}{3} = -\frac{1}{3}

For the points (1,4)(-1, 4) and (2,3)(2, 3): slope=342(1)=13=13\text{slope} = \frac{3 - 4}{2 - (-1)} = \frac{-1}{3} = -\frac{1}{3}

For the points (2,3)(2, 3) and (6,2)(6, 2): slope=2362=1413\text{slope} = \frac{2 - 3}{6 - 2} = \frac{-1}{4} \neq -\frac{1}{3}

Since the slope is not consistent, D does not represent a linear function.

Conclusion:

Set A represents a linear function.

Would you like further details on how to calculate slopes or have any other questions? Here are some related topics:

  1. What is the formula for calculating the slope of a line?
  2. How can we recognize if a set of points forms a function?
  3. What is the difference between a linear function and a nonlinear function?
  4. How do we graph a linear function from a set of ordered pairs?
  5. How can the slope-intercept form of a linear equation be derived from a set of points?

Tip: Always check if the slope between different points is consistent to verify whether the relationship is linear!

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Slope
Ordered Pairs
Linear Equations

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)

Theorems

A function is linear if the slope between any two points is constant.

Suitable Grade Level

Grades 8-10