y=-7x-3. is (-6,-39) a solution? reference (x,y)

To determine if \((-6, -39)\) is a solution to the equation \(y = -7x - 3\), we substitute \(x = -6\) into the equation and check if the corresponding \(y\) value is \(-39\).

Substitute \(x = -6\) into the equation:
\[
y = -7(-6) - 3
\]

Simplify the expression:
\[
y = 42 - 3 = 39
\]

The equation gives \(y = 39\) when \(x = -6\). However, the point \((-6, -39)\) has \(y = -39\). Since \(39 \neq -39\), \((-6, -39)\) is **not** a solution to the equation \(y = -7x - 3\).

Would you like more details or have any other questions?

Here are 5 related questions:
1. How do you determine if a point is a solution to a linear equation?
2. What are the steps to graphing a linear equation like \(y = -7x - 3\)?
3. How do you find the slope and y-intercept from an equation in the form \(y = mx + b\)?
4. What happens when you substitute an incorrect point into an equation?
5. How can you solve for \(x\) when given \(y\) and the equation of a line?

**Tip:** Always double-check your substitution steps to avoid errors in determining solutions.

Explore whether the point (-6, -39) satisfies the equation y = -7x - 3 through substitution and verification. Understand the process of checking solutions to linear equations. Suitable for Grades 7-9 mathematics education.

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