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The question is asking which points from the given options lie on the graph of the equation \( y = -3x + 2 \). We will substitute the \( x \)-coordinates of each point into the equation and check if the corresponding \( y \)-coordinates match.

**Equation:**
\[
y = -3x + 2
\]

### a) \( (-1, 5) \)

Substitute \( x = -1 \) into the equation:
\[
y = -3(-1) + 2 = 3 + 2 = 5
\]
This matches the given \( y \)-coordinate. So, point \( (-1, 5) \) **lies on the graph**.

### b) \( (0, 2) \)

Substitute \( x = 0 \) into the equation:
\[
y = -3(0) + 2 = 0 + 2 = 2
\]
This matches the given \( y \)-coordinate. So, point \( (0, 2) \) **lies on the graph**.

### c) \( (2, -5) \)

Substitute \( x = 2 \) into the equation:
\[
y = -3(2) + 2 = -6 + 2 = -4
\]
This does not match the given \( y \)-coordinate (which is \( -5 \)). Therefore, point \( (2, -5) \) **does not lie on the graph**.

### Conclusion:
Points \( (-1, 5) \) and \( (0, 2) \) lie on the graph of \( y = -3x + 2 \).

Do you want more details or have any questions?

Here are 5 related questions you can consider:
1. What is the slope of the line \( y = -3x + 2 \)?
2. How do you find the y-intercept from a linear equation?
3. Can two points determine a unique line? Why or why not?
4. What would the equation of a line be if it was parallel to \( y = -3x + 2 \)?
5. How can you graph \( y = -3x + 2 \) using its slope and intercept?

**Tip:** To check if a point lies on a graph, always substitute the coordinates into the equation and verify the results.

Vilken eller vilka av punkterna ligger på grafen till y = -3x + 2?

This problem helps students understand how to verify whether given points lie on the graph of a linear equation, specifically y = -3x + 2. It covers fundamental concepts of linear equations and graphing. Suitable for students in Grades 7-9.

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