Math Problem Statement

Let V = R^2 and define two binary operations on V, the vector addition and scalar multiplication as (u1, v1) ⊕ (u2, v2) = (u1 + u2 + 3, v1 + v2 - 5) for all (u1, v1), (u2, v2) ∈ V; a ⊙ (u, v) = (au - sa + s, av - ta + t) for all (u, v) ∈ V, a ∈ R, respectively and for some scalar s, t; then determine s, t for which (V, ⊕, ⊙) is a vector space.

Solution

We are given the set V=R2V = \mathbb{R}^2 along with two binary operations on VV, namely vector addition \oplus and scalar multiplication \odot, defined as follows:

For vector addition: (u1,v1)(u2,v2)=(u1+u2+3,v1+v25)(u_1, v_1) \oplus (u_2, v_2) = (u_1 + u_2 + 3, v_1 + v_2 - 5) For scalar multiplication: a(u,v)=(ausa+s,avta+t)a \odot (u, v) = (au - sa + s, av - ta + t) where ss and tt are some scalar values to be determined. We are asked to find ss and tt such that (V,,)(V, \oplus, \odot) forms a vector space.

Conditions for a Vector Space

For (V,,)(V, \oplus, \odot) to form a vector space, the following conditions must hold:

  1. Associativity of Addition: For all (u1,v1),(u2,v2),(u3,v3)V(u_1, v_1), (u_2, v_2), (u_3, v_3) \in V, we must have: ((u1,v1)(u2,v2))(u3,v3)=(u1,v1)((u2,v2)(u3,v3)).((u_1, v_1) \oplus (u_2, v_2)) \oplus (u_3, v_3) = (u_1, v_1) \oplus ((u_2, v_2) \oplus (u_3, v_3)).

  2. Commutativity of Addition: For all (u1,v1),(u2,v2)V(u_1, v_1), (u_2, v_2) \in V, we must have: (u1,v1)(u2,v2)=(u2,v2)(u1,v1).(u_1, v_1) \oplus (u_2, v_2) = (u_2, v_2) \oplus (u_1, v_1).

  3. Additive Identity: There must be an element (0,0)V(0, 0) \in V such that for all (u,v)V(u, v) \in V: (u,v)(0,0)=(u,v).(u, v) \oplus (0, 0) = (u, v).

  4. Additive Inverse: For each (u,v)V(u, v) \in V, there must be an element (u,v)V(-u, -v) \in V such that: (u,v)(u,v)=(0,0).(u, v) \oplus (-u, -v) = (0, 0).

  5. Distributivity of Scalar Multiplication: Scalar multiplication should distribute over vector addition: a((u1,v1)(u2,v2))=(a(u1,v1))(a(u2,v2)).a \odot ((u_1, v_1) \oplus (u_2, v_2)) = (a \odot (u_1, v_1)) \oplus (a \odot (u_2, v_2)).

  6. Distributivity over Scalars: For all a,bRa, b \in \mathbb{R} and (u,v)V(u, v) \in V, we must have: (a+b)(u,v)=(a(u,v))(b(u,v)).(a + b) \odot (u, v) = (a \odot (u, v)) \oplus (b \odot (u, v)).

  7. Scalar Identity: For the scalar 1R1 \in \mathbb{R} and any (u,v)V(u, v) \in V, we must have: 1(u,v)=(u,v).1 \odot (u, v) = (u, v).

Key Conditions to Focus On

The commutativity of addition and the identity conditions for addition and scalar multiplication are often the most restrictive, so we'll start by testing those to determine values for ss and tt.

Let's begin by solving for ss and tt.It appears that there are no nontrivial solutions for ss and tt based solely on the commutativity of addition and scalar identity conditions. This suggests that the given operations for \oplus and \odot might not lead to a valid vector space structure for any choice of ss and tt.

In summary, it seems that the operations defined for vector addition and scalar multiplication violate the basic axioms of a vector space, particularly the commutativity of addition and the scalar identity condition. Therefore, no values of ss and tt will allow (V,,)(V, \oplus, \odot) to form a valid vector space.

Do you have any specific parts you'd like to explore further, or would you like a more detailed explanation of vector space axioms?

Here are some related questions you could consider:

  1. How is scalar multiplication typically defined in vector spaces?
  2. What are the key properties of vector addition in vector spaces?
  3. Why is the identity element important in vector spaces?
  4. What would happen if we changed the definitions of \oplus or \odot?
  5. How do distributivity laws function in vector spaces?

Tip: When determining if a set with operations forms a vector space, always test basic axioms like commutativity and scalar identity first—they're often the quickest indicators of potential issues.

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Math Problem Analysis

Mathematical Concepts

Vector Spaces
Vector Addition
Scalar Multiplication
Axioms of Vector Spaces

Formulas

(u1, v1) ⊕ (u2, v2) = (u1 + u2 + 3, v1 + v2 - 5)
a ⊙ (u, v) = (au - sa + s, av - ta + t)

Theorems

Vector Space Axioms
Commutativity of Addition
Scalar Identity

Suitable Grade Level

Undergraduate Level (Linear Algebra)