Math Problem Statement

In the given figure, P=60 lb .

The image displays a boom supported by a cable.Cable A C is pin-supported at point A. Boom B C is pin-supported at point B. Point B is directly below point A. Cable A C is inclined at an angle of 65 degrees with the vertical. Boom B C is inclined at an angle of 35 degrees with the vertical. Cable A C is connected to boom B C at point C. 2 forces act at point C. The first force is marked P and it is directed vertically down. The second force has a magnitude of 75 pounds and it is at an angle of 25 degrees with the vertical. The required tension in cable AC is 100.899 lb

Determine the corresponding magnitude of the resultant.

The corresponding magnitude of the resultant is lb

Solution

We need to determine the magnitude of the resultant force at point C, given the following conditions:

  • Force P=60lbP = 60 \, \text{lb} is acting vertically downward.
  • A second force of 75lb75 \, \text{lb} is acting at an angle of 2525^\circ with the vertical.
  • The tension in cable AC is 100.899lb100.899 \, \text{lb}.

Step 1: Break Forces into Components

First, let's break the forces into their horizontal and vertical components.

Force P:

Since PP acts vertically downward:

  • Horizontal component: Px=0P_x = 0
  • Vertical component: Py=60lbP_y = -60 \, \text{lb} (negative because it is downward)

Second Force (75 lb):

Given the force is at an angle of 2525^\circ with the vertical, we can break it into horizontal and vertical components using trigonometric functions:

  • Horizontal component: Fx=75sin(25)F_x = 75 \sin(25^\circ)
  • Vertical component: Fy=75cos(25)F_y = 75 \cos(25^\circ)

Step 2: Resultant Components

The total horizontal and vertical components of the resultant force are the sums of the individual components.

  • Horizontal component of the resultant: Rx=Px+Fx=0+75sin(25)R_x = P_x + F_x = 0 + 75 \sin(25^\circ)

  • Vertical component of the resultant: Ry=Py+Fy=60+75cos(25)R_y = P_y + F_y = -60 + 75 \cos(25^\circ)

Step 3: Magnitude of the Resultant

The magnitude of the resultant force RR can be found using the Pythagorean theorem:

R=Rx2+Ry2R = \sqrt{R_x^2 + R_y^2}

Let me calculate that for you.The magnitude of the resultant force at point C is approximately 32.68lb32.68 \, \text{lb}.

Would you like further details or have any questions?

Here are five related questions to expand on this:

  1. How would the result change if the angle of the second force was 30 degrees instead of 25 degrees?
  2. What effect would doubling the force PP have on the resultant?
  3. How would you calculate the tension in the cable if the forces acting were different?
  4. What role does the angle between the cable and boom play in this type of analysis?
  5. How can you determine the direction of the resultant force?

Tip: Always break forces into their horizontal and vertical components to simplify resultant calculations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Vector Decomposition
Trigonometry
Resultant Forces

Formulas

Pythagorean theorem: R = √(R_x^2 + R_y^2)
Component decomposition: F_x = F * sin(θ), F_y = F * cos(θ)

Theorems

Pythagorean Theorem
Trigonometric Functions

Suitable Grade Level

Grades 10-12