https://file.aiquickdraw.com/mathbot/file/1727445127020iu8fbnnp.jpg

To determine whether the lines are parallel, skew, or intersecting, let's analyze the parametric equations of the lines:

### Line \( L_1 \):
\[
x = 3 + 2t,\quad y = 4 - 2t,\quad z = 1 - 3t
\]
where \( t \) is the parameter.

### Line \( L_2 \):
\[
x = 1 + 4s,\quad y = 3 - s,\quad z = 4 + 5s
\]
where \( s \) is the parameter.

### Step 1: Check if the lines are parallel
For two lines to be parallel, their direction vectors must be scalar multiples of each other. The direction vector for \( L_1 \) is derived from the coefficients of \( t \):
\[
\vec{d_1} = \langle 2, -2, -3 \rangle
\]
The direction vector for \( L_2 \) is derived from the coefficients of \( s \):
\[
\vec{d_2} = \langle 4, -1, 5 \rangle
\]
Now, check if \( \vec{d_1} \) and \( \vec{d_2} \) are scalar multiples of each other. If they are not, the lines are not parallel.

Clearly, there is no constant \( k \) such that \( \vec{d_1} = k \vec{d_2} \), so the lines are **not parallel**.

### Step 2: Check if the lines are intersecting
For the lines to intersect, there must be values of \( t \) and \( s \) that make the coordinates \( (x, y, z) \) the same for both lines. This means we solve the system of equations:
\[
3 + 2t = 1 + 4s
\]
\[
4 - 2t = 3 - s
\]
\[
1 - 3t = 4 + 5s
\]

Let's solve this system of equations to check if there are solutions for \( t \) and \( s \).

### Solving the system:
From the first equation:
\[
3 + 2t = 1 + 4s \quad \Rightarrow \quad 2t - 4s = -2 \quad \Rightarrow \quad t = 2s - 1
\]

Substitute \( t = 2s - 1 \) into the second equation:
\[
4 - 2(2s - 1) = 3 - s
\]
\[
4 - 4s + 2 = 3 - s
\]
\[
6 - 4s = 3 - s \quad \Rightarrow \quad 3s = 3 \quad \Rightarrow \quad s = 1
\]

Substitute \( s = 1 \) into \( t = 2s - 1 \):
\[
t = 2(1) - 1 = 1
\]

### Step 3: Verify with the third equation
Substitute \( s = 1 \) and \( t = 1 \) into the third equation:
\[
1 - 3(1) = 4 + 5(1)
\]
\[
1 - 3 = 4 + 5 \quad \Rightarrow \quad -2 \neq 9
\]
This is a contradiction, so the lines do **not intersect**.

### Step 4: Conclusion
Since the lines are neither parallel nor intersecting, they must be **skew**.

Thus, the correct answer is:
\[
\boxed{\text{skew}}
\]

Would you like further clarification on any part of the solution?

Here are 5 related questions to explore:
1. What conditions must hold for two lines to be parallel in 3D space?
2. Can two lines be skew in 2D space, or does this concept only apply to 3D?
3. How can we geometrically visualize skew lines in 3D space?
4. What methods are used to find the shortest distance between two skew lines?
5. How do direction vectors influence the nature of the relationship between two lines?

**Tip**: When checking if lines are parallel, focus on their direction vectors. If these vectors are proportional, the lines are guaranteed to be parallel.

Determine whether the lines L₁: x = 3 + 2t, y = 4 - 2t, z = 1 - 3t and L₂: x = 1 + 4s, y = 3 - s, z = 4 + 5s are parallel, skew, or intersecting.

Explore whether the lines L₁: x = 3 + 2t, y = 4 - 2t, z = 1 - 3t and L₂: x = 1 + 4s, y = 3 - s, z = 4 + 5s are parallel, skew, or intersecting. Learn to use vector analysis and solve parametric equations for 3D geometry.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation