To determine the intervals where $f(x) \geq 0$, we will examine the graph and identify where the function lies on or above the x-axis (i.e., where the function is either positive or zero).

From the graph:

• The function crosses the x-axis at approximately $x = -6$, $x = -1$, $x = 5$.
• The function is above or on the x-axis in the intervals:
  • From $x = -6$ to $x = -1$ (including the points where $f(x) = 0$, i.e., $x = -6$ and $x = -1$).
  • From $x = 5$ onwards (since the function remains positive beyond $x = 5$).

Thus, the intervals where $f(x) \geq 0$ are:

$[-6, -1] \cup [5, \infty)$

Let me know if you'd like any further clarifications or details!

Related Questions:

1. How do we determine the intervals where a function is decreasing?
2. How can we use the derivative to find where $f(x) \geq 0$?
3. What happens when a function crosses the x-axis more than twice?
4. How can concavity affect the intervals where $f(x) \geq 0$?
5. How can we apply this analysis to real-world problems like profit functions?

Tip: When solving graph-based questions, always identify the critical points (such as where the graph crosses the x-axis) to break down the intervals.