Math Problem Statement

A 5-kg object is sliding to the right and encountering a friction force which slows it down. The coefficient of friction between the object and the surface is 0.1. Determine the force of gravity, the normal force, the force of friction, and the acceleration. (Neglect air resistance).

Solution

The problem in the image is about a 5-kg object sliding on a surface and experiencing a frictional force. Let's go through the solution step by step.

Given:

  • Mass of the object, m=5kgm = 5 \, \text{kg}
  • Coefficient of friction, μ=0.1\mu = 0.1
  • Gravitational acceleration, g=9.8m/s2g = 9.8 \, \text{m/s}^2
  • The object is sliding to the right and experiences friction.

To Find:

  1. The force of gravity, FgF_g
  2. The normal force, NN
  3. The frictional force, FfF_f
  4. The acceleration, aa

1. Force of Gravity FgF_g

The force of gravity acting on the object is calculated as: Fg=mgF_g = m \cdot g Substituting the values: Fg=5kg9.8m/s2=49NF_g = 5 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 49 \, \text{N}

2. Normal Force NN

Since the object is sliding on a horizontal surface and there is no vertical acceleration, the normal force is equal in magnitude to the gravitational force: N=Fg=49NN = F_g = 49 \, \text{N}

3. Frictional Force FfF_f

The frictional force is given by the equation: Ff=μNF_f = \mu \cdot N Substituting the values: Ff=0.149N=4.9NF_f = 0.1 \cdot 49 \, \text{N} = 4.9 \, \text{N}

4. Acceleration aa

The net force on the object in the horizontal direction is the frictional force, which is acting to decelerate the object. Newton's second law states that: Fnet=maF_{\text{net}} = m \cdot a Here, Fnet=FfF_{\text{net}} = -F_f (because friction opposes the motion). Thus, the acceleration is: a=Ffm=4.9N5kg=0.98m/s2a = \frac{-F_f}{m} = \frac{-4.9 \, \text{N}}{5 \, \text{kg}} = -0.98 \, \text{m/s}^2 The negative sign indicates that the acceleration is in the opposite direction of the motion, meaning the object is slowing down.


Final Answers:

  1. Force of gravity Fg=49NF_g = 49 \, \text{N}
  2. Normal force N=49NN = 49 \, \text{N}
  3. Frictional force Ff=4.9NF_f = 4.9 \, \text{N}
  4. Acceleration a=0.98m/s2a = -0.98 \, \text{m/s}^2

Would you like more details on any part of this solution?


5 Related Questions:

  1. What happens to the frictional force if the coefficient of friction is increased?
  2. How would the acceleration change if the mass of the object were doubled?
  3. What is the role of the normal force in determining the frictional force?
  4. How does the force of gravity change if the object is on an inclined plane?
  5. How would the acceleration change if the surface had no friction?

Tip:

The coefficient of friction depends on both the materials of the object and the surface. A higher coefficient results in a larger frictional force, which can cause quicker deceleration.

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Math Problem Analysis

Mathematical Concepts

Classical Mechanics
Newton's Laws of Motion
Friction

Formulas

Force of gravity F_g = m * g
Normal force N = F_g
Frictional force F_f = μ * N
Newton's second law F_net = m * a

Theorems

Newton's Second Law of Motion

Suitable Grade Level

High School (Grades 10-12)