Math Problem Statement

Determine whether the following functions are even, odd, or neither: 1. f(x) = (x^3 - 1)/x 2. g(x) = x(x + 1) 3. h(x) = sqrt(1 - x^2) 4. k(x) = 4x^3

Solution

The image contains four questions asking whether each given function is odd, even, or neither.

Let's analyze each function one by one:

1. Function 1: f(x)=x31xf(x) = \frac{x^3 - 1}{x}

  • Odd Function: A function f(x)f(x) is odd if f(x)=f(x)f(-x) = -f(x).
  • Even Function: A function f(x)f(x) is even if f(x)=f(x)f(-x) = f(x).

Calculating f(x)f(-x):

f(x)=(x)31x=x31x=x31x=x3+1xf(-x) = \frac{(-x)^3 - 1}{-x} = \frac{-x^3 - 1}{-x} = \frac{-x^3 - 1}{-x} = \frac{x^3 + 1}{x}

This is not equal to f(x)f(x) or f(x)-f(x). Therefore, the function is neither even nor odd.

2. Function 2: g(x)=x(x+1)g(x) = x(x + 1)

Calculating g(x)g(-x):

g(x)=(x)((x)+1)=(x)(x+1)=x(x1)g(-x) = (-x)((-x) + 1) = (-x)(-x + 1) = x(x - 1)

Since g(x)g(x)g(-x) \neq g(x) and g(x)g(x)g(-x) \neq -g(x), the function is neither even nor odd.

3. Function 3: h(x)=1x2h(x) = \sqrt{1 - x^2}

Calculating h(x)h(-x):

h(x)=1(x)2=1x2h(-x) = \sqrt{1 - (-x)^2} = \sqrt{1 - x^2}

Since h(x)=h(x)h(-x) = h(x), the function is even.

4. Function 4: k(x)=4x3k(x) = 4x^3

Calculating k(x)k(-x):

k(x)=4(x)3=4(x3)=4x3k(-x) = 4(-x)^3 = 4(-x^3) = -4x^3

Since k(x)=k(x)k(-x) = -k(x), the function is odd.

Conclusion:

  1. Function 1 is neither.
  2. Function 2 is neither.
  3. Function 3 is even.
  4. Function 4 is odd.

Would you like further details on any of these explanations, or do you have any questions?

Here are some related questions to deepen your understanding:

  1. What are the conditions for a function to be even or odd?
  2. How can we graphically determine if a function is even or odd?
  3. What are some examples of functions that are both even and odd?
  4. What happens to the symmetry of a function if we add or multiply by another function?
  5. Can a function that is neither even nor odd be split into a sum of an even and an odd function?

Tip: Checking the symmetry of a function is often easiest by substituting xx with x-x and comparing the result to the original function.

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Math Problem Analysis

Mathematical Concepts

Function Symmetry
Even and Odd Functions
Algebra

Formulas

f(-x) = f(x) (Even Function)
f(-x) = -f(x) (Odd Function)
f(-x) ≠ f(x) and f(-x) ≠ -f(x) (Neither)

Theorems

Even and Odd Function Theorem

Suitable Grade Level

Grades 9-12