Math Problem Statement

Given the polar equation r=(4)/(9+5cos(theta)), find the eccentricity, equation of the directrix (which should be a fraction), and the shape of the curve

Solution

To analyze the given polar equation

r=49+5cosθr = \frac{4}{9 + 5 \cos \theta}

we can determine the eccentricity, directrix, and shape of the curve by comparing this form to the standard polar equation of a conic section:

r=ed1+ecosθr = \frac{ed}{1 + e \cos \theta}

where:

  • ee is the eccentricity,
  • dd is the distance from the pole (origin) to the directrix.

Step 1: Identifying the Eccentricity

To match the given equation to the standard form, we rewrite it as:

r=49+5cosθ=491+59cosθr = \frac{4}{9 + 5 \cos \theta} = \frac{\frac{4}{9}}{1 + \frac{5}{9} \cos \theta}

From this form, we can see that:

  • The coefficient of cosθ\cos \theta in the denominator is 59\frac{5}{9}, which corresponds to the eccentricity ee.

Thus, the eccentricity is:

e=59e = \frac{5}{9}

Step 2: Identifying the Shape of the Curve

The shape of a conic section depends on the eccentricity ee:

  • If 0e<10 \leq e < 1, it is an ellipse.
  • If e=1e = 1, it is a parabola.
  • If e>1e > 1, it is a hyperbola.

Since e=59<1e = \frac{5}{9} < 1, the curve is an ellipse.

Step 3: Finding the Directrix

In the polar form of a conic, r=ed1+ecosθr = \frac{ed}{1 + e \cos \theta}, the parameter dd is the distance to the directrix. From our form of the equation:

ed1+ecosθ=49\frac{ed}{1 + e \cos \theta} = \frac{4}{9}

we identify that:

ed=4ed = 4

Solving for dd:

d=4e=459=4×95=365d = \frac{4}{e} = \frac{4}{\frac{5}{9}} = \frac{4 \times 9}{5} = \frac{36}{5}

Thus, the equation of the directrix is:

x=365x = \frac{36}{5}

Summary of Results

  1. Eccentricity (e): 59\frac{5}{9}
  2. Shape of the Curve: Ellipse
  3. Equation of the Directrix: x=365x = \frac{36}{5}

Would you like a detailed breakdown of any step? Here are some related questions:

  1. How can eccentricity determine the shape of a conic section?
  2. What happens if the eccentricity equals 1 in polar equations?
  3. How is the directrix used to define conic sections?
  4. What are the applications of polar equations in real-world scenarios?
  5. Can we convert this polar equation to Cartesian coordinates?

Tip: Eccentricity values offer a quick way to identify conic shapes in polar and Cartesian forms.

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Conic Sections
Eccentricity
Directrix

Formulas

r = ed / (1 + e cos(theta))
Directrix distance d = constant/eccentricity

Theorems

Conic Section Eccentricity and Shape Classification

Suitable Grade Level

Grades 11-12