Math Problem Statement

You wish to determine if there is a linear correlation between the two variables at a significance level of
α

0.01 . You have the following bivariate data set.

x y 12.7 82.7 68.1 -0.6 33.2 62.7 17.1 58.4 46.4 38.2 83.1 -1.5 76.5 14.1

What is the critival value for this hypothesis test? rc.v. = 0.875 Correct

What is the correlation coefficient for this data set? r =

Your final conclusion is that... There is insufficient sample evidence to support the claim the there is a correlation between the two variables. There is sufficient sample evidence to support the claim that there is a statistically significant correlation between the two variables.

Note: In your calculations, round both r and t to 3 decimal places in ALL calculations.

Solution

To address this hypothesis test for correlation, we need to calculate the correlation coefficient, rr, for the data set and then compare it to the critical value rc.v.=0.875r_{c.v.} = 0.875 at a significance level of α=0.01\alpha = 0.01. We will then determine if there is sufficient evidence to conclude a statistically significant correlation between the variables.

Step 1: Calculate the Correlation Coefficient rr

The formula for the sample correlation coefficient rr is:

[ r = \frac{n \sum (x y) - \sum x \sum y}{\sqrt{\left[n \sum x^2 - (\sum x)^2\right] \left[n \sum y^2 - (\sum y)^2\right]}} ]

where:

  • nn is the number of data points,
  • x\sum x is the sum of all xx-values,
  • y\sum y is the sum of all yy-values,
  • xy\sum xy is the sum of the products of each xx and yy value,
  • x2\sum x^2 is the sum of each xx-value squared,
  • y2\sum y^2 is the sum of each yy-value squared.

Let’s calculate each of these values:

  1. n=7n = 7
  2. x=12.7+68.1+33.2+17.1+46.4+83.1+76.5\sum x = 12.7 + 68.1 + 33.2 + 17.1 + 46.4 + 83.1 + 76.5
  3. y=82.70.6+62.7+58.4+38.21.5+14.1\sum y = 82.7 - 0.6 + 62.7 + 58.4 + 38.2 - 1.5 + 14.1
  4. xy\sum xy: Calculate each product x×yx \times y and then sum them.
  5. x2\sum x^2: Square each xx-value and sum.
  6. y2\sum y^2: Square each yy-value and sum.

Step 2: Interpret rr

Once rr is calculated, we compare it to rc.v.r_{c.v.}:

  • If r0.875|r| \geq 0.875, there is sufficient evidence of a statistically significant correlation.
  • If r<0.875|r| < 0.875, there is insufficient evidence of correlation.

Calculation of rrThe calculated correlation coefficient rr is approximately 0.953-0.953.

Step 3: Conclusion

Since r=0.953|r| = 0.953 is greater than the critical value rc.v.=0.875r_{c.v.} = 0.875, we have sufficient evidence to support the claim that there is a statistically significant correlation between the two variables at the α=0.01\alpha = 0.01 significance level.

Final Conclusion

There is sufficient sample evidence to support the claim that there is a statistically significant correlation between the two variables.


Would you like further details on any step or have any questions?

Here are five related questions:

  1. How does the significance level α\alpha affect the critical value in a correlation test?
  2. What is the interpretation of a negative correlation coefficient like r=0.953r = -0.953?
  3. How does sample size impact the correlation coefficient’s reliability?
  4. What alternative methods exist to assess correlation other than the Pearson correlation?
  5. How does outlier presence affect the calculation and interpretation of correlation?

Tip: In hypothesis testing for correlation, a larger sample size generally makes it easier to detect small correlations as significant.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Hypothesis Testing
Correlation Coefficient

Formulas

Correlation coefficient formula: r = (nΣ(xy) - ΣxΣy) / √[(nΣ(x²) - (Σx)²)(nΣ(y²) - (Σy)²)]
Critical value comparison for correlation hypothesis test

Theorems

Correlation hypothesis testing
Significance level and critical value in hypothesis testing

Suitable Grade Level

College Level Statistics