Consider the following data representing the price of refrigerators (in dollars).

1388,1384,1152,1085,1352,1162,1229,1464,1412,1258,1475,1329,1376,1122,1468,1443,1283,1182,1207,1310,11781388,1384,1152,1085,1352,1162,1229,1464,1412,1258,1475,1329,1376,1122,1468,1443,1283,1182,1207,1310,1178

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Price of Refrigerators (in Dollars)ClassFrequencyClass BoundariesMidpointRelative FrequencyCumulative Frequency

1080–11491080–1149

1150–12191150–1219

1220–12891220–1289

1290–13591290–1359

1360–14291360–1429

1430–14991430–1499

Step 1 of 7 :

Determine the class width of the classes listed in the frequency table.

To determine the **class width** for the classes listed in the frequency table, we use the following formula:

\[
\text{Class width} = \text{Upper boundary of a class} - \text{Lower boundary of the same class}
\]

Looking at the class boundaries for the first class (1080–1149):

\[
\text{Class width} = 1149 - 1080 = 69
\]

Thus, the **class width** is **69**.

Would you like to proceed with the next steps or have any other questions?

### 5 Related Questions:
1. How is class width related to the overall distribution of data?
2. Can the class width vary between different frequency tables?
3. How can we use class width to create histograms?
4. What would happen if we change the class width to a smaller or larger value?
5. How do class boundaries differ from class intervals?

### Tip:
When choosing class width, it is essential to ensure that the intervals are neither too wide (which can hide details) nor too narrow (which can cause over-clustering of data).

Determine the class width of the classes listed in the frequency table for the price of refrigerators.

Learn how to calculate the class width for a frequency table representing refrigerator prices. This problem introduces key statistical concepts such as class intervals, class boundaries, and class width. Suitable for students in Grades 9-12.

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