Math Problem Statement
Solution
Let's analyze the question and solve each part step-by-step based on the information in the image:
Part (a): Find the amplitude, period, and horizontal shift.
-
Amplitude:
- The amplitude is the maximum absolute value of from the center line (horizontal axis). In this graph, the maximum value of is and the minimum is .
- Therefore, the amplitude is .
-
Period:
- The period is the distance along the -axis that it takes for the wave to complete one full cycle.
- In the graph, the sine curve completes one cycle from to .
- Thus, the period is .
-
Horizontal Shift:
- The horizontal shift refers to any left or right displacement of the wave.
- The graph appears to start at without any horizontal shift.
- Therefore, the horizontal shift is .
Part (b): Write an equation that represents the curve in the form .
- Given values:
- Amplitude () is .
- Period () is , which implies .
- Horizontal Shift () is .
Thus, the equation of the sine wave is:
Summary:
- Amplitude:
- Period:
- Horizontal Shift:
- Equation:
Would you like more details on any specific part of this solution?
Related Questions:
- How would the equation change if the amplitude was halved?
- What would happen to the period if was doubled?
- How would a horizontal shift of affect the equation?
- How can you rewrite this equation as a cosine function?
- How would the graph look if the amplitude was negative?
Tip:
When identifying the period of a sine or cosine function, remember that it is given by where is the coefficient of in the function or .
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Sine Function
Amplitude
Period
Phase Shift
Formulas
y = a sin(k(x - b))
Amplitude = max(|y|)
Period = 2π / k
Theorems
Properties of Sine Functions
Suitable Grade Level
High School (Grades 10-12)
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